Answer:
0.0198 mm/sec
Explanation:
Given:
d = 8 cm
L = 10 m = 1000 cm
v = 200 m/min
E = 100%
density = 3500 A.m^-2
Using Faraday's law of electrolysis, we have:
Q = n(e) * F
Where,
Q = electric charge
F = Faraday's constant=96500Cmol
n(e) = electron charge = 2
Therefore
Q= 96500 * 2 = 193000
Let's find the area of pipe, A = πr²(L)
But radius, r =
Therefore,
A = 3.142 * 4² * 1000
A = 50272
To find the thickness of the coating deposited, we have :
= 0.0198 mm/sec
Answer:
Detailed solution is given in the attached diagram
Answer:
The block will float with its axis vertical.
Explanation:
For it to float, the upward force on the cylindrical block must be equal to the weight of an equal volume of water. Also, this upward force must be greater than or equal to the weight of the cylindrical block for it to float.
So, weight of cylindrical block, W = specific weight × volume
specific weight = 7500 N/m³
volume = πd²h/4 where d = diameter of block and h = height of block
volume = π(1 m)² × 1 m/4 = π/4 m³ = 0.7854 m³
W = 7500 N/m³ × 0.7854 m³ = 5890.5 N
Since the density of water = 1000 kg/m³, its specific weight W' = 1000 kg/m³ × 9.8 m/s² = 9800 N/m³
Since the volume of the cylinder = volume of water displaced, the weight of water displaced W' = upward force = specific weight of water × volume of water displaced = 9800 N/m³ × 0.7854 m³ = 7696.92 N
Since W' = 7696.92 N > W = 5890.5 N, <u>the block will float with its axis vertical since the upward force is greater than the weight of the cylindrical block.</u>
Answer:
A rivet is a mechanical fastener composed of a head on one end and a cylindrical stem on another (called the tail) which has the appearance of a metal pin.
When installed the rivet is either drilled, placed or punched into a hole, afterwards the tail is then deformed, holding the rivet in place. When finished the tail has the appearance of a dumbbell shape completing the riveted joint.
Answer:
11.52 hp
Explanation:
<u><em>Givens: </em></u>
p_1 = 15 pisa
p_2 = 70 pisa
V_ol=1.5 ft^3/s
<u><em>Solution: </em></u>
Note: m = p x V_ol (assuming in compressible flow —> p =const)
The total change in the system mechanical energy can be calculated as follows,
Δ
e= (p_2 - p_1 ) /p
The power needed can be calculated as follows
P = W =mΔ
e = p x V_ol x(p_2 - p_1 ) /p
= V_ol x (p_2 - p_1 )
= 44 pisa. ft^3/s
= 44 x (1 btu/5.404pisa. ft^3) x (1 hp/0.7068btu/s)
= 11.52 hp