How does the "E" in STEM work with the other letters
1 answer:
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Answer:
check the explanation
Explanation:
1.
Thickness Loss =
Hence Rate of Corrosion = = 0.03 inches per year
2.
As the expected future life is 7 years,
40 carbon steel pipe has to be replaced every 3 years as given in the question,
Cost per unit length is the sum of material cost and installation cost.
Cost of 40 carbon steel = (5 dollars + 16.5 dollars) * 3 = 64.5 dollars
For 80 carbon steel pipe, first calculate the thickness loss,
The critical thickness is given to be 3mm, Hence change in thickness is 8.55-3 = 5.5mm
This 80 carbon steel pipe has to be replaced one more time
Hence, Cost per unit length is the sum of material cost and installation cost.
Cost of 80 carbon steel = (8.3 dollars + 16.5 dollars) * 2 = 49.6 dollars
The best is of stainless steel which does not undergo corrosion at all and thus it needs to be replaced only once throughout the plant operation. Its cost = 24.8 dollars + 16.5 dollars = 41.3 dollars
Hence, stainless steel is the recommended pipe to be used.
Answer:
Enthalpy at outlet=284.44 KJ
Explanation:
We need to Find enthalpy of outlet.
Lets take the outlet mass m and outlet enthalpy h.
So from mass conservation
m=1+1.5+2 Kg/s
m=4.5 Kg/s
Now from energy conservation
By putting the values
So h=284.44 KJ
Answer:
8 mm
Explanation:
Given:
Diameter, D = 800 mm
Pressure, P = 2 N/mm²
Permissible tensile stress, σ = 100 N/mm²
Now,
for the pipes, we have the relation as:
where, t is the thickness
on substituting the respective values, we get
or
t = 8 mm
Hence, the minimum thickness of pipe is 8 mm