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IRISSAK [1]
3 years ago
15

Electrical circuits must be locked-out/tagged-out before electricians work on any equipment. Is this true or false?

Engineering
1 answer:
dybincka [34]3 years ago
8 0

Answer:

true

Explanation:

Equipment that are "locked-out/tagged-out" <em>prevent the electrician from being electrocuted</em> or attaining a serious injury in relation to it. Locking out an equipment prevents it from releasing its energy because such energy can be <em>hazardous</em> to the electrician. There are instances when the equipment accidentally starts up, thus, it is essential that the equipment's source of energy is<em> isolated.</em>

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Briefly discuss if it would be better to operate with pumps in parallel or series and how your answer would change as the steepn
Aleksandr [31]

Answer:

1) In series, the combined head will move from point 1 to point 2 in theory. However, practically speaking, the combined head and flow rate will move along the system curve to point 3.

2) In parallel, the combined head and volume flow will move along the system curve from point 1 to point 3.

Explanation:

1) Pump in series:

When two or more pumps are connected in series, their resulting pump performance curve will be obtained by adding their respective heads at the same flow rate as shown in the first diagram attached.

In the first diagram, we have 3 curves namely:

- system curve

- single pump curve

- 2 pump in series curve

Also, we have points labeled 1, 2 and 3.

- Point 1 represents the point that the system operates with one pump running.

- Point 2 represents the point where the head of two identical pumps connected in series is twice the head of a single pump flowing at the same rate.

- Point 3 is the point where the system is operating when both pumps are running.

Now, since the flowrate is constant, the combined head will move from point 1 to point 2 in theory. However, practically speaking, the combined head and flow rate will move along the system curve to point 3.

2) Pump in parallel:

When two or more pumps are connected in parallel, their resulting pump performance curve will be obtained by adding their respective flow rates at same head as shown in the second diagram attached.

In the second diagram, we have 3 curves namely:

- system curve

- single pump curve

- 2 pump in series curve

Also, we have points labeled 1, 2 and 3

- Point 1 represents the point that the system operates with one pump running.

- Point 2 represents the point where the flow rate of two identical pumps connected in series is twice the flow rate of a single pump.

- Point 3 is the point where the system is operating when both pumps are running.

In this case, the combined head and volume flow will move along the system curve from point 1 to point 3.

5 0
3 years ago
BE-40 What is a characteristic of a catamaran hull?
Nat2105 [25]

Answer:

<em>A stable ride</em>

Explanation:

A Catamaran hull is a form of sea craft invented by the Austronesian peoples, the invention of the Catamaran hull enabled these people to sail across the sea in their expansion to the islands of the Indian and Pacific Oceans. Catamaran has multiple hulls, usually two parallel hulls of equal size. This geometric feature gives the craft an increased stability because,<em> it derives extra stability from its wide beam, in the place of a ballasted keel employed in a regular monohull sailboat. </em>A Catamaran hull will require four times the force needed to capsize it, when compared to an equivalent monohull.

8 0
3 years ago
t is desired to produce aligned carbon fiber-epoxy matric composite having a longitudinal tensile strength of 800 MPa. Given (a)
Nesterboy [21]

Answer:

The value of critical length = 3.46 mm

The value of volume of fraction of fibers = 0.43

Explanation:

Given data

\sigma_{T} =  800 M pa

D = 0.017 mm

L = 2.3 mm

\sigma_{f} = 5500 M pa

\sigma_{m} = 18 M pa

\sigma_c = 13.5 M pa

(a) Critical fiber length is given by

L_{c} = \sigma_{f} (\frac{D}{2 \sigma_{c} } )

Put all the values in above equation we get

L_{c} =5500 (\frac{0.017}{(2) (13.5)} )

L_{c} = 3.46 mm

This is the value of critical length.

(b).Since this  critical length is greater than fiber length Than the volume fraction of fibers is given by

V_{f} = \frac{\sigma_T - \sigma_m}{\frac{L\sigma_c}{D} - \sigma_m }

Put all the values in above formula we get

V_{f} = \frac{800-18}{\frac{(2.3)(13.5)}{0.017} - 18 }

V_{f} = 0.43

This is the value of volume of fraction of fibers.

3 0
3 years ago
Plane wall of material A with internal heat generation is insulated on one side and bounded by a second wall of material B, whic
viktelen [127]

Sorry❤

Have a nice day ✨

8 0
3 years ago
FD=CD*((P*(V^2)*A)/2)<br><br>Please solve for V
REY [17]

Answer:

The answer is V = √2FD ÷ CD × PA

Explanation:

FD = CD × PV²A ÷ 2

V² = 2FD ÷ CD × PA

V = √2FD ÷ CD × PA

Thus, The value of V is V = √2FD ÷ CD × PA

 

<u>-TheUnknownScientist 72</u>

7 0
2 years ago
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