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scoundrel [369]
3 years ago
11

Which is an effect of gravity on objects on the surface of Earth? Check all that apply.

Physics
1 answer:
timama [110]3 years ago
3 0

• Objects “fall” toward the center of Earth.  (TRUE)

Since the gravitational force between earth and any object is always along the line joining the centers of two so all the objects near the surface of earth will always feel force towards the centre of the earth due to gravity.

• Objects are pulled by Earth but do not pull on Earth.  (FALSE)

Since gravitational force will always follow Newton's III law as per which every action has equal and opposite reaction force so object near the surface of earth will also pull the earth as earth is pulling the object towards the center.

• Objects accelerate at a rate of 9.8 m/s each second.  (TRUE)

Since acceleration due to gravity of Earth is 9.8 m/s^2 so here we can say that all objects near the surface of earth will accelerate towards the center of earth at rate of 9.8 m/s^2 due to gravitational pull.

• Objects travel at a rate of 9.8 m/s to are the center of Earth. (FALSE)

Since earth is pulling all objects near its surface with gravitational force so objects can not move at constant speed but it will move with constant acceleration.

• Objects are pulled by Earth more strongly than they pull on Earth. (FALSE)

Since gravitational force will always follow Newton's III law which say every action has equal and opposite reaction so we can say that force due to all objects on earth will be same as the force of earth on the object.

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To solve this problem it is necessary to apply the concepts related to the conservation of Energy. Mathematically the conservation of kinetic energy must be paid in the increase of potential energy or vice versa. This expressed in algebraic terms is equivalent to

Kinetic Energy = Potential Energy

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Where

m = Mass

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h = Height

As the mass is the same then we have to

\frac{1}{2} v^2 = gh

Rearrange to find v,

v = \sqrt{2gh}

Our values are given as

g = 1.6m/s^2

h = 7.8m

Therefore replacing we have

v = \sqrt{2(1.6)(7.8)}

v = 4.99m/s

Hence the velocity at the moon would be 4.99m/s

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4 0
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Answer:

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Explanation:

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