<u>¹⁴₇N</u><u> </u>is the more stable isotope
<h3>
Briefly explained</h3>
We have ¹⁴₇N which has a neutron to proton ratio of one, and we look at ¹⁸₇N which has a neutron to proton ratio of 1.57 Again, you look at table 24 to and you see the atomic number of seven and there is really no stable isotope. It has any more than 10 neutrons.
When we have eight, protons will go down seven protons. There's really nothing stable that has more than maybe eight neutrons. So the fact that we have 11 neutrons with ¹⁸₇N suggests that this is very unstable and
¹⁴₇N is the stable isotope of the pair.
<h3>
Stable and Unstable Nuclei</h3>
An atom is electrically neutral. It contains an equal number of positively charged protons and negatively charged electrons and their charges balance. The nucleus however contains only positively charged protons which are closely packed together in a very small volume (remember neutrons have no charge).
From the laws of physics (Coulomb’s Law) one would expect that the protons being of the same charge and so close together would exert strong repulsive forces on each other. The combined gravitational force from the protons and neutrons in a nucleus is insignificant as an attractive force because their masses are so tiny.
This implies there must be an additional attractive force similar in size to the electrostatic repulsion which holds the nucleus together.
Learn more about stable and unstable nuclei
brainly.com/question/24748035
#SPJ4
<span>Select the block of cells to be included in the scatter plot by clicking and dragging, then from the Insert ribbon under Chart drop down the Scatter or Bubble menu and select Scatter. A chart will appear on the spreadsheet.
</span><span>
To set up a scatter plot in Excel, enter the pairs of data in two columns with each value of a pair on the same row. By default, Excel considers the column on the left to contain the horizontal (X) values and the column on the right to contain the vertical (Y) values.
</span><span>If you click on the + sign at the upper right of the chart, a list of checkboxes will appear. Check Axes, Axis Titles, and Trendline. Uncheck everything else. You should edit the Axis Titles to include the name of the factor and any units associated with it. Double-click on the Axis numbers to bring up the Format Axis dialog, then click on the bar-graph icon to access Axis Options. Set the bounds and units appropriately and set the tick marks to something sensible.</span><span>
</span>
"B. The radiant sun.
The Sun, like all stars, is a huge plasma ball of very high density and temperature. It consists almost entirely of hydrogen, with a small component of helium and all other elements in smaller proportions.
Although the plasma in the deep interior of the Sun has a chaotic movement, towards its surface and on it the movements of the plasma are already more ordered. Below the surface of the Sun the plasma circulates up and down, forming cells called convection, and on the surface and already in its atmosphere the movements of the plasma are strongly controlled by local magnetic fields of varying intensity and varied structure."
Answer:
116.1 a.m.u.
It is not likely that RCOOH is the pentanoic acid
Explanation:
Let's consider the generic neutralization between NaOH and a monoprotic carboxylic acid.
RCOOH(aq) + NaOH(aq) ⇒ RCOONa(aq) + H₂O(l)
The molar ratio of RCOOH to NaOH is 1:1. The moles of RCOOH are:

The molar mass of RCOOH is:

Thus, the molecular weight is 116.1 a.m.u.
Pentanoic acid has the formula C₅H₁₀O₂ with a molecular weight of 102.1 a.m.u. So, it is not likely that RCOOH is the pentanoic acid.