Answer:
Explanation:
check the attachment below
If you wanted to neutralize 4.00g NaOH, what volume (l) of 1.0 M HCl would you need?
1 answer:
The balanced reaction between NaOH and HCl is as follows
NaOH + HCl ----> NaCl + H₂O
stoichiometry of NaOH to HCl is 1:1
molar mass of NaOH is 40 g/mol
number of moles =
therefore number of NaOH moles - 4.00 g / 40 g/mol = 0.100 mol
since molar ratio of HCl to NaOH is 1:1
number of HCl moles required = 0.100 mol
Molarity of HCl is 1.0 M
this means that a volume of 1 L contains 1.0 mol
therefore volume containing 0.100 mol - 0.100 mol / 1.0 mol/L = 0.10 L
volume of HCl required = 100 mL
NaOH + HCl ----> NaCl + H₂O
stoichiometry of NaOH to HCl is 1:1
molar mass of NaOH is 40 g/mol
number of moles =
therefore number of NaOH moles - 4.00 g / 40 g/mol = 0.100 mol
since molar ratio of HCl to NaOH is 1:1
number of HCl moles required = 0.100 mol
Molarity of HCl is 1.0 M
this means that a volume of 1 L contains 1.0 mol
therefore volume containing 0.100 mol - 0.100 mol / 1.0 mol/L = 0.10 L
volume of HCl required = 100 mL
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Answer: A pressure of 0.681 atm would be exerted by 0.023 grams of oxygen if it occupies 31.6 mL at
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Explanation:
Given : Mass of oxygen = 0.023 g
Volume = 31.6 mL
Convert mL into L as follows.
Temperature =
As molar mass of is 32 g/mol. Hence, the number of moles of
are calculated as follows.
Using the ideal gas equation calculate the pressure exerted by given gas as follows.
PV = nRT
where,
P = pressure
V = volume
n = number of moles
R = gas constant = 0.0821 L atm/mol K
T = temperature
Substitute the value into above formula as follows.
Thus, we can conclude that a pressure of 0.681 atm would be exerted by 0.023 grams of oxygen if it occupies 31.6 mL at
.
I would assume so.
Given
, we can simplify the fraction to 
Both would obtain the same proportions, so I don't see why putting a half cup of sugar would make things any different.
Hope this is the answer you are looking for.
Given
Both would obtain the same proportions, so I don't see why putting a half cup of sugar would make things any different.
Hope this is the answer you are looking for.