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romanna [79]
3 years ago
15

Given mass and force, one can caluclate acceleration a) true b) false

Physics
1 answer:
slega [8]3 years ago
7 0

So the gist of this answer would be in search engines

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A book is sitting on a desk. What best describes the normal force acting on the book?
Sladkaya [172]
My best guess would be:

"A force equal in magnitude but opposite in direction"

However I assume that this question is multiple choice, by the way it is introduced. Therefore it would be helpful if these options were also displayed - hence take this as my best guess only.
5 0
3 years ago
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Josh is designing a lab to separate a mixture of sulfur powder and iron filings. He looks at all the ways to separate a mixture
Stolb23 [73]

Answer:

D) magnetic attraction

Explanation:

Mixture consists of sulfur powder and iron filings . The former is non magnetic and the later is magnetic material . The best way to separate them is to use a magnet . This method is called magnetic separation method . A magnet will attract the iron filling but the sulfur will remain un-attracted . Thus, the two will get separated from each other.

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3 years ago
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Internal diameter of a test tube<br>​
sladkih [1.3K]

Answer:

16 mm with 14 mm inside diameter.

4 0
3 years ago
A car of mass 1800 kg collides with a truck of mass 5200 kg, and just after the collision the car and truck slide along, stuck t
kupik [55]

Explanation:

Elastic collision is said to occur if the total kinetic energy is not conserved and if there is a rebound after collision

Step one

Analysis of the problem

Immediately after impact the car's velocity was zero making it a perfect elastic collision

Step two

Given

Mass of car M1=1800kg

Mass of truck M2=5200kg

Initial velocity of Car U1=44m/s

Initial velocity of truck U2=21m/s

Final velocity of car V1= 0m/s

Final velocity of truck V2=20m/s

Step three

According to the principle of conservation of momentum

Total momentum before collision

=M1U1+M2U2

Total momentum after impact

=M1V1+M2V2

M1U1+M2U2 =M1V1+M2V2

Substituting our data into the expression we have 1500*44+5800*21=1500*0+5800*20

=66000+1218000=11600

1284000=11600

From the solution the momentum before impact is 1284000Ns

Momentum after impact is 11600Ns

This is indicating that after impact there was loss in momentum as a result of the car having a velocity of zero

8 0
4 years ago
What is watt equivalent to in terms of kg,m and s
daser333 [38]

F=ma=kg*m/s^2=N

Work=W=Force*d=N*m

P=W/time=N*m/s=kg*m^2/s^3=kg*m^2*s^-3=Watt

So 1 Watt of Power is equivalent to (kg*m^2)/s^3 or kg*m^2*s^-3


Any questions please feel free to ask. Thank you

3 0
4 years ago
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