the answer to your question is c
A.3n+4+3n+4+4n
=3n+3n+4n+4+4
=10n+8
B.11n+4+n-12
=11n+n+4-12
=12n-8
C.6(6n-2)
=36n-12
D.4(3n-2)
=12n-8
E.4n+22-12+8n
=4n+8n+22-12
=12n+10
so,B and D are the expressions that are equivalent to 12n-8.
<h3><u>
Answer:</u></h3>
Hence, the sum of a 7-term geometric series is:
-32766.
<h3><u>
Step-by-step explanation:</u></h3>
We have to find the sum of a 7-term geometric series (i.e. n=7) if the first term(a) is -6, the last term is -24,576, and the common ratio(r) is 4.
We know that the sum of the 7-term geometric series is given as:

On putting the value of a,n and r in the given formula we have:

Hence, the sum of a 7-term geometric series is:
-32766.
Answer:
C. solution:
3(3c-2) = 5(2c-1)
or, 9c-6 = 10c-5
or, -6+5 =<em> </em>10c-9c
or, -1 = 1c
Hence, c = -1.
D. solution:
5(5-2a) = 4(6-a)
or, 25-10a = 24 - 4a
or, 25-24 = -4a+10a
or, 1 = 6a
or, 1/6 = a
Hence, a = 1/6.