Question

HELP!!!! FAST!!!! 20 POINTS!!!! You are a traffic accident investigator. You have arrived at the scene of an accident. Two trucks of equal
mass (3,000 kg each) were involved in a rear-end accident at a stop sign. Here is what you know:
• Truck 1 started from rest at the top of a 22-meter hill and coasted toward the intersection.
.
Truck 2 was on a flat stretch of road at the bottom of the hill directly in front of Truck 1.
At the bottom of the hill, Truck 1 was going 20 m/s; Truck 2 was going 35 m/s.
.
There were no skid marks left by Truck 2. The collision occurred at the stop sign where Truck 2 had
stopped
• After the collision, both trucks moved together in the same direction at 10 m/s before slowly rolling
to a stop.
You must now push Truck 2, using 1,000 N of force, 8 meters off to the side of the road so no one
else gets hurt.
1. How much work was done to bring truck 2 to a stop? 2. If tuck 2 came to a stop In 15 seconds, how much power (in watts) did it take to stop truck 2 at the sign by applying force to the brakes? 3. What is the final combined momentum of the trucks right after the accident? 4. Assuming that there are no other no conservation forces involved, what impulse was given to each truck during the collision? A. Truck 1: B. Truck 2:

Answer 1

Answer:

1) Kinetic energy of the truck 1 is 600,000 joules.

Kinetic energy of the truck 2 is 1,837,500 joules.

2 a)Potential energy of truck 1 is 646,800 Joules.

b) Energy lose by the truck 1 just got converted into heat and sound energy during the collision.

Step-by-step explanation:

Mass of the truck 1 and truck 2,m = 3000 kg

Velocity of the truck 1,  = = 20 m./s

Velocity of the truck 2, = 35 m./s

1. Kinetic energy of the truck 1:

Kinetic energy of the truck 2:

2.a) Energy loose by the truck 1:

Initial height of the truck on the hill = 22 m

At that height potential energy will be maximum:

Potential energy of truck 1 at that height =

b) Energy lost by the truck 1 just got converted into heat and sound energy during the collision.