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Vladimir [108]
2 years ago
13

Calculate the density of sulfuric acid from the information that 35.4 mL of the acid masses 65.14 g.

Chemistry
1 answer:
vladimir1956 [14]2 years ago
3 0

Answer:

<h3>The answer is 1.84 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question we have

density =  \frac{65.14}{35.4}  \\  = 1.840112994...

We have the final answer as

<h3>1.84 g/mL</h3>

Hope this helps you

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Using what you have learned about the three forms of writing chemical equations, classify each of the presented equations as eit
suter [353]

Explanation:

Molecular equation: Chemical equation in which molecular formula of reactants and products are written

Complete ionic equation:Chemical equation in which ionic from if reactants reactants and products are written along with spectator ions (ions present on both sides of equation).

Net ionic equation :Chemical equation in which only ions of those reactant are written which giving product without  spectator ions (ions present on both sides of equation).

(a) Ca^{2+}(aq) + SO_4^{2-}(aq)\rightarrow CaSO_4(s)

net ionic equation.

(b) CuSO_4(aq) + 2KOH(aq)\rightarrow Cu(OH))_2(s) + K_2SO_4(aq)

Molecular equation

(c)Ba^{2+} (aq) + SO_4^{2-}(aq)\rightarrow BaSO_4(s)

Net ionic equation.

(d) Ag^+(aq) + NO_{3}^-(aq) + I^-(aq)\rightarrow AgI(s) + NO_{3}^-(aq)

Complete ionic equation

3 0
3 years ago
A compound is found to contain 11.21 % hydrogen and 88.79 % oxygen by mass. What is the empirical formula for this compound?
Artemon [7]

Answer:

H₂O

Explanation:

The empirical formular of the compound is obtained using the following steps;

Step 1: Divide the percentage composition by the atomic mass

Hydrogen = 11.21 / 1 = 11.21

Oxygen = 88.79  / 16 = 5.55

Step 2: Divide by the lowest number

Hydrogen  = 11.21 / 5.55 = 2.02 ≈ 2

Oxygen = 5.55 / 5.55 = 1

This means the ratio of the elements is 2 : 1

The empirical formular (simplest formular of a compound) of the compound is;

H₂O

7 0
2 years ago
Read 2 more answers
Determine the equilibrium constant, Keq, at 25°C for the reaction
adelina 88 [10]

Explanation:

The given chemical reaction is:

2Br^- (aq) + I_2(s)  Br_2(l) + 2I^- (aq)

E^ocell=oxidation potential of anode + reduction potential of cathode\\

The relation between Eo cell and Keq is shown below:

deltaG=-RTlnK_e_q\\delta=-nFE^o cell\\=>nFE^o cell=RTlnK_e_q\\lnK_e_q=\frac{nF}{RT} E^o cell

The value of Eo cell is:

Br- undergoes oxidation and I2 undergoes reduction.

Reduction takes place at cathode.

Oxidation takes place at anode.

Hence,

E^ocell= (-1.07+0.53)V\\=-0.54V

F=96485 C/mol

n=2 mol

R=8.314 J.K-1.mol-1

T=298K

Substitute all these values in the above formula:

ln K_e_q=\frac{2mol* 96485 C/mol}{8.314 J.K^-^1.mol^-^1x298K} \\\\lnK_e_q=77.8\\K_e_q=e^7^7^.^8\\=>K_e_q=6.13x10^3^3

Answer:

Keq=6.13x10^33

3 0
2 years ago
Can someone help me with these. I don’t understand how to answer them or do the work
ICE Princess25 [194]
How am I supposed to help you if there's not picture of what the problem is
6 0
3 years ago
The atmosphere surrounding Earth helps to maintain the various climates found around the world and keeps Earth from becoming ext
riadik2000 [5.3K]

Answer:

The atmosphere traps heat energy from the Sun and energy radiated from Earth's surface helping to maintain Earth's climate

Explanation:

Earth's atmosphere keeps much of the Sun's energy from escaping into space. This process, called the greenhouse effect, keeps the planet warm enough for life to exist. The atmosphere allows about half of the Sun's heat energy (50%) to reach Earth's surface.

4 0
2 years ago
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