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Gala2k [10]
2 years ago
8

3 Draw energy transfer diagrams

Physics
1 answer:
timofeeve [1]2 years ago
6 0

Answer:

The outline of the energy transfer are;

a) Kinetic energy → Clockwork spring → Potential energy

b) Potential energy in clockwork car → Clockwork spring coil unwound → Clockwork car run

c) Chemical potential energy → Batteries in the car → Electric motors → Kinetic energy

Please find attached the drawings of the energy transfer created with MS Visio

Explanation:

The energy transfer diagrams are diagrams that can be used to indicate the part of a system where energy is stored and the form and location to which the energy is transferred

a) The energy transfer diagram for the winding up a clockwork car is given as follows;

Mechanical kinetic energy is used to wind up (turn) the clockwork car such that the kinetic energy is transformed into potential energy and stored in the wound up clockwork as follows;

Kinetic energy → Clockwork spring → Potential energy

b) Letting a wound up clockwork car run results in the conversion of mechanical potential energy into kinetic (energy due tom motion) energy as follows;

Potential energy in clockwork car → Clockwork spring coil unwound → Clockwork car run

c) The energy stored in the battery of a battery powered car is chemical potential energy. When the battery powered car runs, the chemical potential energy produces an electromotive force which is converted into kinetic energy as electric current flows from the batteries

Therefore, we have;

Chemical potential energy → Batteries in the car → Electric motors → Kinetic energy

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Consider two objects (Object 1 and Object 2) moving in the same direction on a frictionless surface. Object 1 moves with speed v
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Answer:

A)Object 1 has the greater magnitude of its momentum.

B)The objects 2 have the greater kinetic energy.

Explanation:

For object 1 :

v₁ = v  ,m₁ = 2 m

For object 2 :

v_2=2\sqrt{v} ,m₂=m

We know that linear momentum given as

P = M V

M=Mass , V=Velocity

For object 1 :

P₁ =m₁ v₁

P₁ =2 m v

For object 2

P_2=m_2v_2

P_2=2m\sqrt {v}

We can say that object 1 have more momentum.

The kinetic energy

KE_1=\dfrac{1}{2}m_1v_1^2

KE_1=\dfrac{1}{2}\times 2m\times v^2

KE_1=mv^2

KE_2=\dfrac{1}{2}m_2v_2

KE_2=\dfrac{1}{2}\times m\times 4v^2

KE_2=2mv^2

Therefore both the object 2 have higher kinetic energy.

7 0
3 years ago
A 1500-W electric heater is plugged into the outlet of a 120-V circuit that has a 20-A circuit breaker. You plug an electric hai
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Answer:

900 W.      

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Given that

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P ' = 2400 - 1500

P'= 900 W

So the answer is 900 W.

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Answer:

directly proportional to the square of its speed.

Explanation:

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