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alexira [117]
2 years ago
6

____________loosens up your muscles and brings your heart rate up in a slow, steady way that’s better for your body.

Physics
1 answer:
kenny6666 [7]2 years ago
8 0

Answer:

COOLING DOWN (AFTER WARM UP )

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In a certain process, the energy change of the system is 250 \rm kJ. The process involves 480 \rm kJ of work done by the system.
alisha [4.7K]

Answer:

\Delta Q=-230kJ

Explanation:

Using the first law of thermodynamics:

\Delta U=\Delta Q-W

Where \Delta U is the change in the internal energy of the system, in this case  \Delta U=250kJ, \Delta Q is the heat tranferred, and W is the work,  W=-480kJ with a negative sign since the work is done by the system.

From the previous equation we solve for heat, because it is the unknown variable in this problem

\Delta Q=\Delta U +W

And replacing the known values:

\Delta Q=250kJ +(-480kJ)

\Delta Q=250kJ -480kJ

\Delta Q=-230kJ

The negative sign shows us that the heat is tranferred from the system into the surroundings.

3 0
3 years ago
PLEASE HURRY Which of the following measurements is a measurement of velocity?
madreJ [45]

Answer:

C) 350 m/s N

Explanation:

Velocity is measured in miles per hour or metres per second.

6 0
3 years ago
What is the substance that is broken down in cellular respiration
Harman [31]
Glucose.... have a nice day
4 0
3 years ago
A small 12.00 g plastic ball is suspended by a string in a uniform, horizontal electric field. If the ball is in equilibrium whe
notsponge [240]

Answer:

Q = \frac{0.068}{E}

where E = electric field intensity

Explanation:

As we know that plastic ball is suspended by a string which makes 30 degree angle with the vertical

So here force due to electrostatic force on the charged ball is in horizontal direction along the direction of electric field

while weight of the ball is vertically downwards

so here we have

QE = F_x

mg = F_y

since string makes 30 degree angle with the vertical so we will have

tan\theta = \frac{F_x}{F_y}

tan30 = \frac{QE}{mg}

Q = \frac{mg}{E}tan30

Q = \frac{0.012\times 9.81}{E} tan30

Q = \frac{0.068}{E}

where E = electric field intensity

5 0
3 years ago
A bullet leaves a gun with a horizontal velocity of 100 m/s. Calculate the distance it would travel in 1.3 seconds.
stiks02 [169]

Ignoring air resistance, the bullet's horizontal velocity is constant:

v_x=v_{0x}=100\,\dfrac{\mathrm m}{\mathrm s}

In 1.3 seconds, we can expect it to travel

v_xt=\left(100\,\dfrac{\mathrm m}{\mathrm s}\right)(1.3\,\mathrm s)=130\,\mathrm m

4 0
3 years ago
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