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fgiga [73]
2 years ago
5

A motorcycle is moving with the velocity of 72km/h. If the velocity reaches 40m/s after 0.5m calculate the acceleration

Physics
1 answer:
julsineya [31]2 years ago
3 0

Answer:

1200m/s

Explanation:

initial velocity=72km/h=20m/s

Final velocity=40m/s

Distance=0.5m

Now,

2as=v^2-u^2

or,2*a*0.5=40^2-20^2

or,1a=1200

or,a=1200/1

therefore,acceleration=1200m/s

Plz mark me as brainliest:)

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b) 0.18µC

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a)

i=\frac{4.55\µC}{2.46\µs}*e^{-\frac{9\µs}{2.46\µs}}\\\\i=0.048A

b)

q=q_o*e^{-\frac{t}{\tau}}

q=4.55\µC*e^{-\frac{8\µs}{2.46\µs}}\\q=0.18\µC

c) the maximum current occurs when t=0

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