Answer:
For uniform acceleration
a = (v2 - v1) /t = 2.5 acceleration is constant 2.5
v2 = 2.5 * 4 v1 = 0 at t = 0
v2 = 2.5 m/s^2 * 4 s = 10 m/s
Answer:
Western north america
Explanation:
extending from southern British Columbia through Washington and Oregon to North Calfirona
Answer:
Solution:
As per the question:
Mass of first object, m = 120 kg
Mass of second object, m' = 420 kg
Mass of the third object, M = 69.0 kg
Distance between the m and m', d = 0.380 m
Now,
To calculate the gravitational force on the object of mass, M placed mid-way due to mass, m:
To calculate the gravitational force on the object of mass, M placed mid-way due to mass, m':
To calculate the gravitational force on the object of mass, M placed mid-way due to mass, m and m':
Answer:
<em>The rock reaches a maximum height of 442.225 m and was thrown at a speed of 93.1 m/s</em>
Explanation:
<u>Vertical Launch</u>
The rock is launched up with a certain speed vo, it reaches its highest point at a height h when the speed is zero, and then it stars a free-fall motion until it hits the ground at time t.
The maximum height is given by
The rock takes the same time to reach this point as to return to the ground, thus we can calculate the maximum height
The rock was thrown up at a speed