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adell [148]
3 years ago
8

Draw an accurate, labelled diagram of a thermometer

Physics
1 answer:
olga nikolaevna [1]3 years ago
7 0
You wear very specific on what type of thermometer he wanted and what specific information you wanted so I just made one like this, hope it helps anyway! -Sam

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Describe two energy conversions that take place when you warm a cup of cocoa in a microwave oven.
vampirchik [111]
1.)the microwaves are absorbed by the water molecules in the cocoa. this causes the water molecules to vibrate very fast.

2.)this fast vibration causes the molecules to heat themselves up by means of bumping into each other (friction).
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20 points !!!
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Which types of atoms usually<br> become negative ions?
nalin [4]
Non metal ions gain electrons to become negative ions
5 0
3 years ago
An atom has seven protons, eight neutrons, and six electrons. What type of electrical charge does it possess?
Crank

Answer:

positive

Explanation:

No. of positive charge= 7

No.of negative charge = 6

so 7 - 6 = 1 positive charge

7 0
3 years ago
A pelican flying along a horizontal path drops a fish from a height of 4.7 m. The fish travels 9.3 m horizontally before it hits
slavikrds [6]

Answer:

(A) 9.5 m/s

(B) 5.225 m

Explanation:

vertical height (h) = 4.7 m

horizontal distance (d) = 9.3 m

acceleration due to gravity (g) = 9.8 m/s^{2}

initial speed of the fish (u) = 0 m/s

(A) what is the pelicans initial speed ?

  • lets first calculate the time it took the fish to fall

s = ut + (\frac{1}{2}) at^{2}

since u = 0

s =  (\frac{1}{2}) at^{2}

t = \sqrt{\frac{2s}{a} }

where a = acceleration due to gravity and s = vertical height

t = \sqrt{\frac{2 x 4.7 }{9.8} } = 0.98 s

  • pelicans initial speed = speed of the fish

speed of the fish = distance / time = 9.3 / 0.98 = 9.5 m/s

initial speed of the pelican = 9.5 m/s

(B) If the pelican was traveling at the same speed but was only 1.5 m above the water, how far would the fish travel horizontally before hitting the water below?

vertical height = 1.5 m

pelican's speed = 9.5 m/s

  • lets also calculate the time it will take the fish to fall

s = ut + (\frac{1}{2}) at^{2}

since u = 0

s =  (\frac{1}{2}) at^{2}

t = \sqrt{\frac{2s}{a} }

where a = acceleration due to gravity and s = vertical height

t = \sqrt{\frac{2 x 1.5 }{9.8} } = 0.55 s

 

distance traveled by the fish = speed x time = 9.5 x 0.55 = 5.225 m

8 0
2 years ago
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