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balu736 [363]
3 years ago
15

An object is placed 60 cm in front of a concave mirror whose focal length is 20 cm. What is

Physics
1 answer:
Salsk061 [2.6K]3 years ago
6 0
Şsşsşssşggg 44466. 555
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In astronomy which planet spins slowest on its axis​
sertanlavr [38]
Venus - 4 miles per hour
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What is the mass of a 5000 N car on Earth?
puteri [66]

Answer:

510.2kg

Explanation:

use w=mg then put the value you will get answer

4 0
3 years ago
Four point charges, each having a magnitude of 2:00 C, are fixed at the corners of a square whose edges are 4:00m long. Find the
Vikki [24]

Answer:

Explanation:

Distance of each of the charges from the center are equal . If this distance be d

d = .5 x length of diagonal of square

length of diagonal = 4√2

d = .5 x 4√2

= 2√2

potential at a point

V = k Q / r where k is a constant , Q is charge and r is distance of the point from the charge .

k = 9 x 10⁹

Total potential = \frac{9\times10^9\times3 \times2}{2\sqrt{2} } -\frac{9\times10^9 \times2}{2\sqrt{2} }

= \frac{9\times10^9 \times2\times2}{2\sqrt{2} }

= 9 √2 x 10⁹ V .

5 0
4 years ago
A spinning rigid body has a rotational kinetic energy of 10 j and an angular speed of 10 s−1 . what is its rotational inertia?
boyakko [2]
Rotational kinetic energy = Iω²/2 = 10
I = rotational inertia(moment of inertia)
ω= angular speed = 10 s⁻¹

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6 0
4 years ago
Read 2 more answers
A parallel plate capacitor has a capacitance of 6.78 μF and it is connected to a 12V battery. What is the charge on the capacito
AfilCa [17]

Answer:

8.136×10⁻⁵ J

Explanation:

Applying,

Q = Cv................ Equation 1

Where Q = Charge on the capacitor, v = voltage of the battery, C = capacitance of the capacitor.

From the question,

Given: C = 6.78μF = 6.78×10⁻⁶ F, v = 12 V

Substitute these values into equation 1

Q = (6.78×10⁻⁶ )(12)

Q = 8.136×10⁻⁵ J

Hence the charge on the capacitor is 8.136×10⁻⁵ J

4 0
3 years ago
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