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2 years ago

What is the purpose of delivering medical aid through drones

1 answer:

8 0

Drones can help overcome transport challenges and delays in the delivery of small, low weight supplies, through the re-supply of essential medicines and delivery of medical diagnostic kits and return samples.

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What is biasing and doping

Flura [38]

Answer:

Biasing - Biasing means being unfair to someone or something, and liking the other one or helping them.

Doping - Doping is where a person use drug to get better at sporting and get stronger muscles, such as getting stronger, getting faster and so on. It is mostly used by athletics.

5 0

2 years ago

Read 2 more answers

Drosera magnifica is an organism that was first discovered in 2015.

mestny [16]

Answer:

The correct answer is - Plantae.

Explanation:

Drosera m<em>agnifica</em> is discovered in 2015 for the first time and the characteristics this organism's cell shows are -

- permanent vacuoles

- surrounded by cellulose layer

Vacuoles are present in both Plantae and Animalia kingdom of the eukaryotic organism but in animal cells, there are small and numerous vacuoles present and they are not permanent whereas in plant cells vacuoles are present permanently.

The cell of an animal cell has no surrounding layer other than cell membrane while in the plant cell there is a supporting and protecting layer of cellulose cell wall present.

On the basis of the given characteristics, it is confirmed that the Drosera magnifica belongs to Plantae kingdom.

3 0

2 years ago

A man pushes a 10kg box with a constant acceleration of 5m/s2. What force is applied to the box?

drek231 [11]

FORMULA

$\boxed {F = m \times a}$

F = force
m = mass
a = acceleration

Using the formula

$F = 10 \times 5$

Multiply

$\boxed {\textsf {F = 10 N}}$

8 0

2 years ago

Read 2 more answers

When a man walks across the carpet and reaches for the door knob, why does he get shocked? doorknob Question 3 options: There is

Mumz [18]

The imbalance of electric charges within or on the surface of a material or between materials is known as static electricity. When you grab a doorknob, electrons jump from your hand to the knob .which conducts electricity, giving you a shock.

<h3>What is static electricity?</h3>

The imbalance of electric charges within or on the surface of a material or between materials is known as static electricity.

The charge will persist until it can be moved away by an electric current or an electrical discharge.

when we walk on the carpet with socks our feet slide electrons off the carpet. it leads to leaving you with a slightly negative static charge.

When you grab a doorknob electrons jump from your hand to the knob which conducts electricity giving you a shock.

Due to the static electricity jump from your hand to the knob .which conducts electricity giving you a shock.

To know more about static electricity refer to the link ;

brainly.com/question/821085

3 0

2 years ago

A 5.50 kg sled is initially at rest on a frictionless horizontal road. The sled is pulled a distance of 3.20 m by a force of 25.

kiruha [24]

(a) 69.3 J

The work done by the applied force is given by:

$W=Fd cos \theta$

where:

F = 25.0 N is the magnitude of the applied force

d = 3.20 m is the displacement of the sled

$\theta=30^{\circ}$ is the angle between the direction of the force and the displacement of the sled

Substituting numbers into the formula, we find

$W=(25.0 N)(3.20 m)(cos 30^{\circ})=69.3 J$

(b) 0

The problem says that the surface is frictionless: this means that no friction is acting on the sled, therefore the energy dissipated by friction must be zero.

(c) 69.3 J

According to the work-energy theorem, the work done by the applied force is equal to the change in kinetic energy of the sled:

$\Delta K = W$

where

$\Delta K$ is the change in kinetic energy

W is the work done

Since we already calculated W in part (a):

W = 69.3 J

We therefore know that the change in kinetic energy of the sled is equal to this value:

$\Delta K=69.3 J$

(d) 4.9 m/s

The change in kinetic energy of the sled can be rewritten as:

$\Delta K=K_f - K_i = \frac{1}{2}mv^2-\frac{1}{2}mu^2$ (1)

where

Kf is the final kinetic energy

Ki is the initial kinetic energy

m = 5.50 kg is the mass of the sled

u = 0 is the initial speed of the sled

v = ? is the final speed of the sled

We can calculate the variation of kinetic energy of the sled, $\Delta K$ , after it has travelled for d=3 m. Using the work-energy theorem again, we find

$\Delta K= W = Fd cos \theta =(25.0 N)(3.0 m)(cos 30^{\circ})=65.0 J$

And substituting into (1) and re-arrangin the equation, we find

$v=\sqrt{\frac{2 \Delta K}{m}}=\sqrt{\frac{2(65.0 J)}{5.50 kg}}=4.9 m/s$

6 0

3 years ago