Answer:
It is an amorphous solid and hence also called pseudo solid. So it flows very slowly over thousands of years. It is not visible to the n*ked eye.
Explanation:
The only flaw I can find is you squared 3 instead of cubing it and it will be 27X^4 instead of 9x^4.
This reduces the amount slightly, but the number is still incredibly high (about 10 ^ 5 L is what I've calculated). Your professor might want to point out that this will not be a effective experiment due to the large volume of saturated
The Ksp value of Ca(OH)2 on the site (I used 5.5E-6 [a far more soluble compound than Al(OH)3]) and estimated how much of it will be needed. My calculation was approximately 30 ml. If you were using that much in the experiment, it implies so our estimates for Al(OH)3 are right, that the high amount is unreasonably big and that Al(OH)3 will not be a suitable replacement unless the procedure was modified slightly.
If the hydrogen ion concentration of a solution is 10–10M, is the solution is definitely alkaline. The thing I used to determine that fact is a basic point - pH above 7 is always alkaline, and as a proof, we can see from the task that the concentration of hydroxyl OH- is pretty higher than hydrogen H+, which is a direct characteristic of the alkain solution.Here is a tip for you, I bet it will be useful : >7 = basic <7 = acidic 7 = neutral
Since the heat of combustion of butane is higher than that of propane, butane will produce more heat per gram when burned compared to propane.
The heat of combustion of a compound refers to the heat evolved when one mole of the compound is burnt under standard conditions. This heat of combustion increases from methane upwards.
Since the heat of combustion of alkanes increases according to increasing molar mass, butane will produce more heat per gram when burned compared to propane.
Learn more about heat of combustion: brainly.com/question/25312146