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3 years ago

If [OH-] = 1×10_4, what is the ph of the solution

1 answer:

3 0

If the hydrogen ion concentration of a solution is 10–10M, is the solution is definitely alkaline. The thing I used to determine that fact is a basic point - pH above 7 is always alkaline, and as a proof, we can see from the task that the concentration of hydroxyl OH- is pretty higher than hydrogen H+, which is a direct characteristic of the alkain solution.Here is a tip for you, I bet it will be useful : >7 = basic <7 = acidic 7 = neutral

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Which of the following are examples of electromagnetic waves?

liubo4ka [24]

Answer:

Explanation:

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3 years ago

What change in energy occurs when you burn coal or petroleum??

expeople1 [14]

Chemical energy is converted to thermal energy.

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3 years ago

Read 2 more answers

What is the ph of a solution labeled .30 trimethylamine k for trimethylamine is 7.42 x 10^4

valentina_108 [34]

Answer:the pH is 12

Explanation:

First We need to understand the structure of trimethylamine

Due to the grades of the bond in the nitrogen with a hybridization sp3 is 108° approximately, then is generated a dipole magnetic at the upper side of the nitrogen, this dipole magnetic going to attract a hydrogen molecule of the water making the water more alkaline

C3H9N+ H2O --> C3H9NH + OH-

$k=\frac{[C3H9NH]*[OH-]}{[C3H9N]}$

Then:

The concentration of the trimethylamine is 0.3 and the concentration of the ion C3H9NH is equal to the OH- relying on the stoichiometric equation. We could find the concentration of the OH- ion with the square root of the multiplication between k and the concentration of trimethylamine

[OH-]= $\sqrt{ 0.3*7.42x10^{-4}}$

[OH-]=0.01

pH=14-(-log[OH-])

pH=12

5 0

3 years ago

Explain what you think a compound is

Kryger [21]

Answer:

composed of two or more parts, elements, or ingredients:

Explanation:

6 0

3 years ago

Suppose a gas starts with a volume of 4.52L, temperature of 23 C, and pressure of 102,00 Pa. If the volume changes to 4.83L and

ivanzaharov [21]

Answer:

The answer to your question is P2 = 84.16 kPa

Explanation:

Data

Volume 1 = V1 = 4.52 L Volume 2 = V2 = 4.83 l

Pressure 1 = P1 = 102 kPa Pressure 2 = P2 = ?

Temperature 1 = T1 = 23°C Temperature 2 = T2 = -12°C

Process

1.- Convert the temperature to °K

Temperature 1 = 23 + 273 = 296°K

Temperature 2 = -12 + 273 = 261°K

2.- Use the Combined Gas law to solve this problem

P1V1/T1 = P2V2/T2

-Solve for P2

P2 = P1V1T2 / T1V2

-Substitution

P2 = (102)(4.52)(261) / (296)(4.83)

-Simplification

P2 = 120331.44 / 1429.68

-Result

P2 = 84.16 kPa

8 0

3 years ago