Answer:
![[Fe^{+3}]=0.700 M](https://tex.z-dn.net/?f=%5BFe%5E%7B%2B3%7D%5D%3D0.700%20M)
![[NO_{3}^{-}]=2.10 M](https://tex.z-dn.net/?f=%5BNO_%7B3%7D%5E%7B-%7D%5D%3D2.10%20M)
Explanation:
Here, a solution of Fe(NO₃)₃ is diluted, as the total volume of the solution has increased. The formula for dilution of the compound is mathematically expressed as:
Here, C and V are the concentration and volume respectively. The numbers at the subscript denote the initial and final values. The concentration of Fe(NO₃)₃ is 1.75 M. As ferric nitrate dissociates completely in water, the initial concentration of ferric is also 1.75 M.
Solving for [Fe],
![[Fe^{+3}]=\frac{C_{1}.V_{1}}{V_{2} }](https://tex.z-dn.net/?f=%5BFe%5E%7B%2B3%7D%5D%3D%5Cfrac%7BC_%7B1%7D.V_%7B1%7D%7D%7BV_%7B2%7D%20%7D)
![[Fe^{+3}]=\frac{(1.75).(30.0)}{45.0+30.0 }](https://tex.z-dn.net/?f=%5BFe%5E%7B%2B3%7D%5D%3D%5Cfrac%7B%281.75%29.%2830.0%29%7D%7B45.0%2B30.0%20%7D)
For [NO₃⁻],
There are three moles of nitrate is 1 mole of Fe(NO₃)₃. This means that the initial concentration of nitrate ions will be three times the concentration of ferric nitrate i.e., it will be 5.25 M.
![[NO_{3}^{-}]=\frac{C_{1}.V_{1}}{V_{2} }](https://tex.z-dn.net/?f=%5BNO_%7B3%7D%5E%7B-%7D%5D%3D%5Cfrac%7BC_%7B1%7D.V_%7B1%7D%7D%7BV_%7B2%7D%20%7D)
![[NO_{3}^{-}]=\frac{(5.25)(30.0)}{30.0+45.0 }](https://tex.z-dn.net/?f=%5BNO_%7B3%7D%5E%7B-%7D%5D%3D%5Cfrac%7B%285.25%29%2830.0%29%7D%7B30.0%2B45.0%20%7D)
Answer :
Total carbons are in the structure = 13
Primary carbons are in the structure = 5
Secondary carbons are in the structure = 6
Tertiary carbons are in the structure = 1
Quaternary carbons are in the structure = 1
Explanation :
Primary carbon : It is a carbon atom that is bound to only 1 carbon atom.
Secondary carbon : It is a carbon atom that is bound to 2 carbon atom.
Tertiary carbon : It is a carbon atom that is bound to 3 carbon atom.
Quaternary carbon : It is a carbon atom that is bound to 4 carbon atom.
As we are given the name of compound is, 2,2-dimethyl-4-propyloctane.
In this compound, eight carbon are align in a straight line, two methyl group are attached at 2nd position of the carbon in main chain and a propyl group that is three membered carbon chain is attached at 4th position of the carbon in main chain.
The given compound skeletal structure is shown below.
A.helium<span>Hydrogen is the most abundant element in the Universe; helium is second. However, after this, the rank of abundance does not continue to correspond to the atomic number; oxygen has abundance rank 3, but atomic number 8.</span>
The answer is 9.5 one as it is more basic so it contains more OH ion
Hope it helps : )
THE ANSWER TO THE QUESTION IS A
