<u>Answer:</u> The chemical formula is 
<u>Explanation:</u>
Ionization energy is defined as the amount of energy that is required to remove an electron from a chemical species.
The ionization energy equation for the given values follow:



From the values of ionization energy above, it can be seen that the ionization energy increases as every succeeding electron is removed.
Second ionization energy is a little higher than the first one but there is a huge amount of difference between the third and second ionization energy.
This implies that the ion formed during second ionization energy has a stable configuration and it requires a humongous amount of heat to release the third electron.
Hence, the ion formed will be 
Sulfite ion is a polyatomic ion having a chemical formula of 
An ionic compound is formed between the two ions and the chemical compound formed between the two will have a formula of 
Hence, the chemical formula is 
find mol of N2 present using gas law equation
PV = nRT
P = pressure = 688/760 = 0.905 atm.
V = 100mL = 0.1L
n = ???
R = 0.082057
T = 565+273 = 838
Substitute:
0.905*0.1 = n*0.082057*838
n = 0.0905 / 68.76
n = 0.00132 mol N2
Molar mass N2 = 28 g/mol
0.00132 mol = 0.00132*28 = 0.037g N2 gas
<span>The effective nuclear charge of an atom = total electrons - inner electrons
For O, ENC = 8 - 2 = 6
For Li, ENC = 3 - 2 = 1
For C, ENC = 6 - 2 = 4
The electrons in O experience the greatest effective nuclear charge and that is why O is smaller than C (which is smaller than Li).</span>
The balanced chemical reaction is written as:
<span>4C(s) + S8(s) → 4CS2(l)
We are given the amount of carbon and sulfur to be used in the reaction. We need to determine first the limiting reactant to be able to solve this correctly.
</span>7.70 g C ( 1 mol / 12.01 g) =0.64 mol C
19.7 g S8 ( 1 mol / 256.48 g) = 0.08 mol S8
The limiting reactant would be S8. We use this amount to calculate.
0.08 mol S8 ( 4 mol CS2 / 1 mol S8 ) ( 256.48 g / 1 mol ) = 78.8 g CS2