1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
djverab [1.8K]
2 years ago
13

I NEED HELP ASAP!!!

Chemistry
1 answer:
Rus_ich [418]2 years ago
3 0

Explanation:

To answer this question, we'll need to use the Ideal Gas Law:

p

V

=

n

R

T

,

where

p

is pressure,

V

is volume,

n

is the number of moles

R

is the gas constant, and

T

is temperature in Kelvin.

The question already gives us the values for

p

and

T

, because helium is at STP. This means that temperature is

273.15 K

and pressure is

1 atm

.

We also already know the gas constant. In our case, we'll use the value of

0.08206 L atm/K mol

since these units fit the units of our given values the best.

We can find the value for

n

by dividing the mass of helium gas by its molar mass:

n

=

number of moles

=

mass of sample

molar mass

=

6.00 g

4.00 g/mol

=

1.50 mol

Now, we can just plug all of these values in and solve for

V

:

p

V

=

n

R

T

V

=

n

R

T

p

=

1.50 mol

×

0.08206 L atm/K mol

×

273.15 K

1 atm

= 33.6 L

this is not the answer but it will help you

do by the formula it is on the answer

You might be interested in
I need help pls, and fast.
Vadim26 [7]

Answer:

1) Liquid forms drops that are dome-shaped

2) low surface tension

3) low viscosity

4) Liquid is thick and pours very slowly

Explanation:

It makes sense just use the stuff that's already in the table. It usually works.

7 0
3 years ago
Which of the following is NOT a type of joint?
Setler79 [48]
B. is ur answer I bieleve
8 0
3 years ago
What is the molality of a solution that contains 1.34 moles of NaCl in 2.47 kg of solvent
dsp73

The molality is 0.54 M when 1.34 moles of NaCl is present in 2.47 kg of solvent.

<u>Explanation:</u>

Molality is the measure of how much of amount of solute is dissolved in the solvent. So it is calculated as the ratio of moles of solute to the grams of solvent.

         \text {Molality}=\frac{\text {Moles of solute}}{\text {Mass of solvent}}

As in this case, the solute is NaCl and solvent is unknown. So the moles of solute is given as 1.34 moles and the mass of solvent is given as 2.47 kg.

Hence, \text { molality }=\frac{1.34}{2.47}= 0.54 \mathrm{M}

Thus, the molality is 0.54 M when 1.34 moles of NaCl is present in 2.47 kg of solvent.

8 0
3 years ago
Uranium (VIII) Sulfide formula
tresset_1 [31]

Answer:

US₂

Explanation:

Uranium sulfide (US₂)

Uranium atomic symbol = U

Sulfur atomic symbol = S

Uranium valency = +4

Sulfur valency = -2

So;

Uranium sulfide (US₂)

8 0
3 years ago
Some one please help me ​
Norma-Jean [14]

Answer:

C.4

Explanation:

6 0
3 years ago
Other questions:
  • HELP ASAP PLEASE!!!!!!!!!!!
    9·1 answer
  • A substance that will change shape to fit its container but has a definite volume is in a phase of matter?
    15·2 answers
  • What mass of aluminum is produced by the decomposition of 5.0 kg al2o3?
    7·2 answers
  • Ethanol can react with hydrochloric acid to form chloroethane and water. When sulfuric acid is added, the
    15·1 answer
  • PLEASE HELP!! STOICHIOMETRY!
    9·1 answer
  • Placing a suspect at the scene of a crime is an important element in criminal investigation. This can be achieved through the lo
    11·1 answer
  • How does the light source readout differ from the x-ray readout in the gizmo??
    15·1 answer
  • An endergonic reaction with a Δh and Δs can be changed into an exergonic reaction.
    12·1 answer
  • Difine the term compound​
    12·1 answer
  • 6)Explain why a 0.010 M solution of hydrochloric acid, HCl has a pH of 2.00 but a 0.010 M solution of
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!