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The pH of the solution in which one normal adult dose aspirin is dissolved is : 2.7
Given data :
mass of aspirin = 640 mg = 0.640 g
volume of water = 10 ounces = 0.295735 L
molar mass of aspirin = 180.16 g/mol
moles of aspirin = mass / molar mass = 0.00355 mol
<h3>Determine the pH of the solution </h3>First step : <u>calculate the concentration of aspirin</u>
= moles of Aspirin / volume of water
= 0.00355 / 0.295735
= 0.012 M
Given that pKa of Aspirin = 3.5
pKa = -logKa
therefore ; Ka = =
From the Ice table
=
=
given that the value of Ka is small we will ignore -x
x² =
x =
Therefore
[ H⁺ ] =
given that
pH = - Log [ H⁺ ]
= - ( -3 + log 1.948 )
= 2.71 ≈ 2.7
Hence we can conclude that The pH of the solution in which one normal adult dose aspirin is dissolved is : 2.7
Learn more about Aspirin : brainly.com/question/2070753
Answer:
The volume of water in water bath is 1,011 Liters.
Explanation:
Length of the water bath, L = 1.85 m
Width of the water bath, W= 0.810 m
Height of the water bath ,H= 0.740 m
Height of the water in water bath, h= 0.740 m - 2.57 inches
1 m = 39.37 inch
Volume of the water in bath = L × W × h
The volume of water in water bath is 1,011 Liters.