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<u>Answer:</u> The mass of nitrogen that is present for given amount of aluminium is 566.22 g.
<u>Explanation:
</u>
We are given:
Mass of aluminium = 364 grams
The chemical formula of aluminium nitrate is
Molar mass of nitrogen = 14 g/mol
Molar mass of aluminium = 27 g/mol
In 1 mole of aluminium nitrate, 27 grams of aluminium is combining with 42 grams of nitrogen.
So, 364 grams of aluminium will combine with = of nitrogen.
Hence, the mass of nitrogen that is present for given amount of aluminium is 566.22 g.
Answer:
There is one scientific method
it starts with an
OBSERVATION
then a HYPOTHESIS
which goes to planning, creating an EXPERIMENT
and finally a conclusion for your results
Explanation:
If you mix Ammonia as well as Hydrogen chloride, you will get ammonium chloride. It is given by NH3 (g) + HCl (g) → NH4Cl(s).
Four Consecutive terms are written as a-3, a-1, a+1,a+3. So
Sum of Terms : 4a=28
a=7
So the terms are 4,6,8,10
Verification : 4^2+6^2+8^2+10^2
= 216