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Scrat [10]
3 years ago
11

Which complex number has a distance of radical 17 from the origin on the complex plane?

Mathematics
2 answers:
grandymaker [24]3 years ago
7 0
<h2>Answer:</h2>

<u>The right choice is</u><u> (D) 4-i</u>

<h2>Step-by-step explanation:</h2>

See  the attached image

Inga [223]3 years ago
5 0

Answer: LAST OPTION

Step-by-step explanation:

The complex numbers shown have the form:

a+bi

By definition, the distance can the distance of the complex number from the origin on the complex plane can be calculated with the formula shown below:

d=\sqrt{a^2+b^2}

Substitute values of each option. Then:

1) d=\sqrt{2^2+15^2}=\sqrt{229}

2) d=\sqrt{17^2+1^2}=\sqrt{290}

3) d=\sqrt{20^2+(-3)^2}=\sqrt{409}

4) d=\sqrt{4^2+(-1)^2}=\sqrt{17} (CORRECT OPTION)

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And 9 + 5 = 14

So, your answer is 14

Hope this helps!

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