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RUDIKE [14]
3 years ago
12

A child is swinging back and forth with a constant period and amplitude. Somewhere in front of the child, a stationary horn is e

mitting a constant tone of frequency fs Five points are labeled in the drawing to indicate positions along the arc as the child swings. At which position(s) will the child hear the lowest frequency for the sound from the whistle?
Physics
1 answer:
Amanda [17]3 years ago
3 0

Answer:

Explanation:

  We shall apply concept of Doppler's effect of apparent frequency to this problem . Here observer is moving sometimes towards and sometimes away from the source . When observer moves towards the source , apparent frequency is more than real frequency and when the observer moves away from the source , apparent frequency is less than real frequency . The apparent frequency depends upon velocity of observer . The formula for apparent frequency when observer is going away is as follows .

f = f₀ ( V - v₀ ) / V , f is apparent , f₀ is real frequency , V is velocity of sound and v is velocity of observer .

f will be lowest when v₀ is highest .

velocity of observer is highest when he is at the equilibrium position or at middle point .

So apparent frequency is lowest when observer is at the middle point and going away from the source  while swinging to and from before the source of sound .

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PolarNik [594]

Answer:

Since this is old, im just gonna get these points, don't wan't them to go to waste lm.ao

Explanation:

7 0
3 years ago
An unstable atomic nucleus of mass 1.58 10-26 kg initially at rest disintegrates into three particles. One of the particles, of
lara31 [8.8K]

Answer:

a The velocity of the third particle is v_3 = (-15.629*10^{6}i -14.45*10^{6}j)\ m/s

b The total kinetic energy increase E = 6.50 *10^{-13} J

Explanation:

To solve this question we are going to be using the concept of conservation of momentum which is mathematically represented as

            m_1v_1 +m_2v_2 +m_3v_3 = 0

From the question

        Mass of  unstable atomic nucleus m_0= 1.58 *10^{-26} kg

        Mass of  x-axis particle m_1 = 8.44* 10^{-27} kg

        Velocity of x-axis particle v_ 1 =  4.00* 10^6 m/s

         Mass of  y-axis particle  m_2 =5.20* 10^{-27} kg

            Velocity of y-axis particle  v_2 = 6.00 *10^6 m/s

 Since the initial mass is known we can obtain the mass of the third particle  

 Using the conservation of mass mathematical expression

                m_3 = m_0 - (m_1 +m_2)

                  m_3 = 1.58 *10^{-26}  - ( 8.44* 10^{-27} + 5.20* 10^-27)

                        = 2.16 *10 ^{-27}kg

Using the mathematical expression above for conservation of momentum

               (8.44 * 10^{-27})( 4.00* 10^6i) + (5.20 *10^{-27})(6.00* 10^6j) +(2.16*0^{-27})v_3 =0

            v_3 = (-15.629*10^{6}i -14.45*10^{6}j)\ m/s

The above is the vector solution now to obtain the value in numeric form we evaluate the magnitude of the vector

         Mag  = \sqrt{(15.629*10^6)^2 +(14.45*10^6)^2}

                = 21.285*10^6 \ m/s

To obtain the total increase in  kinetic energy which is mathematically represented as

         E = \frac{1}{2}m_1v_1 +  \frac{1}{2}m_2v_2 + \frac{1}{2} m_3 v_3

         E =\frac{1}{2} [(5.20*10^{-27})(6.0*0^{6})^2 + (8.44*10^{-27})(4.00*10^6)^2+\\\\(2.16*10^{-27})(21.285*10^6)^2]

              = 6.50 *10^{-13} J

5 0
3 years ago
Fill in the blank with the correct word below (from the reading_):
grigory [225]

Answer:I think it’s self monitoring sorry if wrong

Explanation:

4 0
3 years ago
Which statement is not true about light? 1 point It is a particle and a wave It has mechanical and transverse waves It has mecha
belka [17]

Answer:

Option C

Explanation:

Light is an electromagnetic wave as it has characteristics of both electrical and magnetic waves. It is not a mechanical wave. Water and sound wave are mechanical wave as they need some medium to travel while light do not need any medium to travel.

Hence, option C is correct

4 0
3 years ago
Of the following, which have the highest frequency in the electromagnetic
kirill [66]
D. X rays ..........
6 0
3 years ago
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