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RUDIKE [14]
3 years ago
12

A child is swinging back and forth with a constant period and amplitude. Somewhere in front of the child, a stationary horn is e

mitting a constant tone of frequency fs Five points are labeled in the drawing to indicate positions along the arc as the child swings. At which position(s) will the child hear the lowest frequency for the sound from the whistle?
Physics
1 answer:
Amanda [17]3 years ago
3 0

Answer:

Explanation:

  We shall apply concept of Doppler's effect of apparent frequency to this problem . Here observer is moving sometimes towards and sometimes away from the source . When observer moves towards the source , apparent frequency is more than real frequency and when the observer moves away from the source , apparent frequency is less than real frequency . The apparent frequency depends upon velocity of observer . The formula for apparent frequency when observer is going away is as follows .

f = f₀ ( V - v₀ ) / V , f is apparent , f₀ is real frequency , V is velocity of sound and v is velocity of observer .

f will be lowest when v₀ is highest .

velocity of observer is highest when he is at the equilibrium position or at middle point .

So apparent frequency is lowest when observer is at the middle point and going away from the source  while swinging to and from before the source of sound .

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Answer:

a) Resistivity=R.A/L

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=500000*0.00088/1.6 = 440/1.6= 275 ohm.meter

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For second part, correct option is (A), because cross section area is smaller.

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3 years ago
A group of science and engineering students embarks on a quest to make an electrostatic projectile launcher. For their first tri
vekshin1

Electric charge on the plastic cube: 1.3\cdot 10^{-7}C

Explanation:

The electric potential around a charged sphere (such as the Van der Graaf) generator is given by

V(r)=\frac{kQ}{r}

where

k is the Coulomb's constant

Q is the charge on the sphere

r is the distance from the centre of the sphere

Here we have:

V = 200,000 V on the surface of the sphere, so at r = 12.0 cm

We need to find the voltage V' at 2.0 cm from the edge of the sphere, so at

r' = 12.0 + 2.0 = 14.0 cm

Since the voltage is inversely proportional to r, we can use:

Vr=V'r'\\V'=\frac{Vr}{r'}=\frac{(200,000)(12.0)}{14.0}=171,429 V

This is the potential at the location of the plastic cube.

Now we can use the law of conservation of energy, which states that the initial electric potential energy of the cube is totally converted into kinetic energy when the plastic cube is at infinite distance from the generator. So we can write:

qV' = \frac{1}{2}mv^2

where:

q is the charge on the plastic cube

V' is the potential at the location of the cube

m = 5.0 g = 0.005 kg is the mass of the cube

v = 3.0 m/s is the final speed of the cube

Solving for q, we find the charge on the cube:

q=\frac{mv^2}{2V'}=\frac{(0.005)(3.0)^2}{2(171,429)}=1.3\cdot 10^{-7}C

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brainly.com/question/8960054

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3 years ago
What is the most likely effect of an increase in precipitation?
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A 124-kg balloon carrying a 22-kg basket is descending with a constant downward velocity of 24.3 m/s . A 1.0-kg stone is thrown
defon

Answer:

-969.06

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698.7

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Explanation:

Given that

Speed v, wrt y = -24.3 m/s

Speed v, wrt x = 12.9 m/s

time t, = 11.8 s

a

Using the formula

H(t) = ut - 1/2gt², where u = v wrt y

H(t) = -24.3 * 11.8 - 1/2 * 9.8 * 11.8²

H(t) = -286.74 - 682.28

H(t) = -969.06 m

b

H = ut, where u = v wrt y

H = -24.3 * 11.8

H = -286.74 m

H(1) = -969.06 - -286.74 = -682 m

c

Horizontal displacement, x = vt. Where v = v wrt x

x = 12.9 * 11.8

x = 152.22 m

d = √(H1² + x²)

d = √682² + 152²

d = 465124 + 23104

d = √488228

d = 698.7 m

d

Vertical component =

-gt - 0 =

-9.8 * 11.8 = -115.6

Horizontal component =

v wrt x - 0

12.9 - 0 = 12.9

e

Vertical component =

-gt - v wrt y =

-9.8 * 11.8 - 24.3 = -139.9

Horizontal component =

v wrt x - 0 =

12.9 - 0 = 0

8 0
3 years ago
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