Answer:
The answer is 12.67 TMU
Explanation:
Recall that,
worker’s eyes travel distance must be = 20 in.
The perpendicular distance from her eyes to the line of travel is =24 in
What is the MTM-1 normal time in TMUs that should be allowed for the eye travel element = ?
Now,
We solve for the given problem.
Eye travel is = 15.2 * T/D
=15.2 * 20 in/24 in
so,
= 12.67 TMU
Therefore, the MTM -1 of normal time that should be allowed for the eye travel element is = 12.67 TMU
Newton's second law states that the resultant of the forces applied to an object is equal to the product between the object's mass and its acceleration:

where in our problem, m is the mass the (child+cart) and a is the acceleration of the system.
We are only concerned about what it happens on the horizontal axis, so there are two forces acting on the cart+child system: the force F of the man pushing it, and the frictional force

acting in the opposite direction. So Newton's second law can be rewritten as

or

since the frictional force is 15 N and we want to achieve an acceleration of

, we can substitute these values to find what is the force the man needs:
Answer:
Momentum change of the rock = 3835 kgm/s
Chane in earth's velocity = 6.4 x 10⁻²² m/s
Explanation:
m = 50.0 kg, M = 6.0 x 10²⁴ kg
d = 300.0 m
final velocity of rock = v, v² = 2gd = 2 * 9.81 * 300, so v = 76.7 m/s
Momentum change of the rock = mv = 50.0 * 76.7 = 3835 kgm/s
Inital momentum of the rock+earth system = 0
final momentum = 0 (momentum conservation)
momentum of rock and momentum of earth are same magnitude and opposite directions.
mv - MV = 0
Chane in earth's velocity = mv/M = 3835/(6.0 x 10²⁴) = 6.4 x 10⁻²² m/s
Answer:

Explanation:
Given data
Baseball mass m₁=0.15 kg
initial speed v₁=0
Bullet mass m₂=0.032 kg
final speed v₂=230 m/s
To find
height h=?
Solution
From conservation of momentum we know that

Now from the conservation of mechanical energy