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daser333 [38]
3 years ago
10

Technician A says that the device that controls shift points on an automatic transmission is the valve body. Technician B says t

hat the device that controls shift points on an automatic transmission is the computer. Who is correct?
A) Technician A only
B) Technician B only
C) Both A and B
D) Neither A nor B
Physics
1 answer:
alexira [117]3 years ago
3 0

Answer: Technician B only

Explanation:

What actually controls the shifting in a automatic transmission is the vehicle's internal computer that helps shift the gears automatically. This includes a Control Module that adjusts the current provided to solenoids inside to control the gears The hydraulic system is used to select gears dependent on the transmission fluid's pressure applied.

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American football uses a field that is 100.0yd long, whereas the a soccer field is 100.0m long. Which field is longer and by how
Vitek1552 [10]
The soccer field is  9.36%  longer. 
8 0
3 years ago
For safety reasons, a worker’s eye travel time in a certain operation must be separated from the manual elements that follow. Th
iogann1982 [59]

Answer:

The answer is 12.67 TMU

Explanation:

Recall that,

worker’s eyes travel  distance must be = 20 in.

The perpendicular distance from her eyes to the line of travel is =24 in

What is the MTM-1 normal time in TMUs that should be allowed for the eye travel element = ?

Now,

We solve for the given problem.

Eye travel is = 15.2 * T/D

=15.2 * 20 in/24 in

so,

= 12.67 TMU

Therefore, the MTM -1 of normal time that should be allowed for the eye  travel element is = 12.67 TMU

7 0
3 years ago
A man pushes his child in a grocery cart. The total mass of the cart and child is 30.0 kg. If the force of friction on the cart
Ber [7]
Newton's second law states that the resultant of the forces applied to an object is equal to the product between the object's mass and its acceleration:
\sum F = ma
where in our problem, m is the mass the (child+cart) and a is the acceleration of the system.

We are only concerned about what it happens on the horizontal axis, so there are two forces acting on the cart+child system: the force F of the man pushing it, and the frictional force F_f acting in the opposite direction. So Newton's second law can be rewritten as
F-F_a = ma
or
F=ma + F_f

since the frictional force is 15 N and we want to achieve an acceleration of a=1.50 m/s^2, we can substitute these values to find what is the force the man needs:
F=(30 kg)(1.5 m/s^2)+15 N=60 N
8 0
3 years ago
A 50.0 kg rock starting from rest free falls through a distance of 300.0 m with no air resistance. Find the momentum change of t
Kobotan [32]

Answer:

Momentum change of the rock = 3835 kgm/s

Chane in earth's velocity = 6.4 x 10⁻²² m/s

Explanation:

m = 50.0 kg, M = 6.0 x 10²⁴ kg

d = 300.0 m

final velocity of rock = v, v² = 2gd = 2 * 9.81 * 300, so v = 76.7 m/s

Momentum change of the rock = mv = 50.0 * 76.7 = 3835 kgm/s

Inital momentum of the rock+earth system = 0

final momentum = 0 (momentum conservation)

momentum of rock and momentum of earth are same magnitude and opposite directions.

mv - MV = 0

Chane in earth's velocity = mv/M = 3835/(6.0 x 10²⁴) = 6.4 x 10⁻²² m/s

5 0
2 years ago
A 0.032-kg bullet is fired vertically at 230 m/s into a 0.15-kg baseball that is initially at rest. How high does the combined b
gogolik [260]

Answer:

heigth=83.44m

Explanation:

Given data

Baseball mass m₁=0.15 kg

initial speed v₁=0

Bullet mass m₂=0.032 kg

final speed v₂=230 m/s

To find

height h=?

Solution

From conservation of momentum we know that

m_{1}v_{1}+m_{2}v_{2}=(m_{1}+m_{2})v\\ (0.032kg)(230m/s)+(0.15kg)(0m/s)=(0.15kg+0.032kg)v\\7.36+0=0.182v\\v=7.36/0.182\\v=40.44m/s

Now from the conservation of mechanical energy

P.E=K.E\\mgh=(1/2)mv^{2}\\ gh=(1/2)v^{2}\\ (9.8m/s^{2} )h=(1/2)(40.44m/s)^{2}\\ (9.8m/s^{2} )h=(817.7m^{2} /s^{2} )\\h=(817.7m^{2} /s^{2} )/9.8m/s^{2}\\ heigth=83.44m

5 0
3 years ago
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