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4 years ago

If a pressure gauge measure

Physics

1 answer:

rjkz [21]4 years ago

7 0

Answer:210000N

Explanation:

pressure=3 x 10^5pa

Area=0.7m^2

Force=pressure x area

Force=3x10^5 x 0.7

Force=210000N

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A rugby player passes the ball 7.88 m across the field, where it is caught at the same height as it left his hand. (Assume the p

damaskus [11]

Explanation:

Given

Range of ball =7.88 m

Initial speed=13.1 m/s

and we know

Range of Projectile is

$R=\frac{u^2sin2\theta }{g}$

$13.1=\frac{13.1^2\times sin2\theta }{9.8}$

$7.88\times 9.8=13.1^2\times sin2\theta$

$sin2\theta =0.4499$

$2\theta =26.74^{\circ}$

$\theta =13.37 ^{\circ}$

(b)other angle would be complementary of $\theta$

$=90-\theta =76.63 ^{\circ}$

8 0

3 years ago

what mass of lead has the same volume as 1600 of alcohol ( density of lead =11300kg\m³ and density of alcohol=790kg\m³)

Misha Larkins [42]

The mass of lead = 22,939 kg

<h3>Further explanation</h3>

Given

mass alcohol=1600 kg

The density of lead =11300kg\m³ and density of alcohol=790kg\m³

Required

mass of lead

Solution

volume of alcohol

$\tt V=\dfrac{mass}{\rho}\\\\V=\dfrac{1600}{790}\\\\V=2.03~m^3$

the volume of lead=volume of alcohol=2.03 m, so the mass of lead :

$\tt m=\rho\times V\\\\m=11300\times 2.03\\\\m=22,939~kg$

7 0

3 years ago

in a billiards game, the white cue ball hits the black ball, moving the black ball to the right while the cue ball moves to the

Gemiola [76]

Answer:

The black ball moving to the right after being struck by the white ball

Explanation:

4 0

3 years ago

A 0.500-kg mass suspended from a spring oscillates with a period of 1.18 s. How much mass must be added to the object to change

olga55 [171]

Answer:

The add mass = 5.465 kg

Explanation:

Note: Since the spring is the same, the length and Tension are constant.

f ∝ √(1/m)........................ Equation 1 (length and Tension are constant.)

Where f = frequency, m = mass of the spring.

But f = 1/T ..................... Equation 2

Substituting Equation 2 into equation 1.

1/T ∝ √(1/m)

Therefore,

T ∝ √(m)

Therefore,

T₁/√m₁ = k

where k = Constant of proportionality.

T₁/√m₁ = T₂/√m₂ ........................ Equation 3

making m₂ the subject of the equation

m₂ = T₂²(m₁)/T₁²........................... Equation 4

Where T₁ = initial, m₁ = initial mass, T₂ = final period, m₂ = final mass.

Given: T₁ = 1.18 s m₁ = 0.50 kg, T₂ = 2.07 s.

Substituting into equation 4

m₂ = (2.07)²(0.5)/(1.18)²

m₂ = 4.285(1.392)

m₂ = 5.965 kg.

Added mass = m₂ - m₁

Added mass = 5.965 - 0.5

Added mass = 5.465 kg.

Thus the add mass = 5.465 kg

7 0

3 years ago

The best method for separating an oil and water mixture would be _____.

Mice21 [21]

Answer:

The answer is density

Explanation:

8 0

3 years ago

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