Let's take the non-linear equation:
![{x}^{2} = \sqrt{3} y](https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20%3D%20%20%5Csqrt%7B3%7D%20y)
First Make The Equation To Be In Terms of Y
*Divide Both sides by
![\sqrt{3}](https://tex.z-dn.net/?f=%20%5Csqrt%7B3%7D%20)
![\frac{ {x}^{2} }{ \sqrt{3} } = \frac{ \sqrt{3} y}{ \sqrt{3} }](https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7Bx%7D%5E%7B2%7D%20%7D%7B%20%5Csqrt%7B3%7D%20%7D%20%20%3D%20%20%5Cfrac%7B%20%5Csqrt%7B3%7D%20y%7D%7B%20%5Csqrt%7B3%7D%20%7D%20)
*Simplify
![\frac{ {x}^{2} }{ \sqrt{3} } = y](https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7Bx%7D%5E%7B2%7D%20%7D%7B%20%5Csqrt%7B3%7D%20%7D%20%20%3D%20y)
You shouldn't keep a radical in the denominator, however we leave it for the purpose of the reciprocal.
*Take The Reciprocal Of Both Sides
![\frac{ \sqrt{3} }{ {x}^{2} } = \frac{1}{y}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%5Csqrt%7B3%7D%20%7D%7B%20%7Bx%7D%5E%7B2%7D%20%7D%20%3D%20%20%5Cfrac%7B1%7D%7By%7D%20%20)
A Linear Equation Takes The Format:
![y = mx + b](https://tex.z-dn.net/?f=y%20%3D%20mx%20%2B%20b)
So,
![\frac{1}{y} = y](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7By%7D%20%20%3D%20y)
![b = 0](https://tex.z-dn.net/?f=b%20%3D%200)
![m(slope) = \frac{ \sqrt{3} }{x}](https://tex.z-dn.net/?f=m%28slope%29%20%3D%20%20%5Cfrac%7B%20%5Csqrt%7B3%7D%20%7D%7Bx%7D%20)
![x = \frac{1}{x}](https://tex.z-dn.net/?f=x%20%3D%20%20%5Cfrac%7B1%7D%7Bx%7D%20)
Resulting in :
This question requires you to covert minutes and seconds to degrees
In the question we have 59 minutes and 60 seconds that needs to be converted.
1°=60 minutes
59 minutes = 59÷60
=0.983333°
60 seconds = 1 minute
1 minute = 0.0166667°
So, <span>24° 59' 60" will be equal to
</span>
24°+0.983333°+0.0166667°= 24.9999997°