Answer:
ions
Explanation:
Individual atoms of the same element but having slightly different number of protons and electrons are called ions.
Ion is a charged particle.
- An atom is made up of three fundamental subatomic particles.
- Protons are the positively charged particles
- Electrons are the negatively charged particles
- Neutrons do not carry any charges.
When the number of protons > electrons the body is positively charged.
When the number of electrons > protons the body is negatively charged.
Charged particles are called ions.
<u>Answer:</u> The chemical equations are given below.
<u>Explanation:</u>
The chemical equation for the reaction of lead nitrate and sodium hydroxide follows:
By Stoichiometry of the reaction:
1 mole of aqueous solution of lead nitrate reacts with 2 moles of aqueous solution of sodium hydroxide to produce 1 mole of solid lead hydroxide and 2 moles of aqueous solution of sodium nitrate.
The chemical equation for the reaction of lead hydroxide and hydroxide ions follows:
![Pb(OH)_2(s)+2OH^-(aq.)\rightarrow [Pb(OH)_4]^{2-}(aq.)](https://tex.z-dn.net/?f=Pb%28OH%29_2%28s%29%2B2OH%5E-%28aq.%29%5Crightarrow%20%5BPb%28OH%29_4%5D%5E%7B2-%7D%28aq.%29)
By Stoichiometry of the reaction:
1 mole of lead hydroxide reacts with 2 moles of aqueous solution of hydroxide ions to produce 1 mole of aqueous solution of tetra hydroxy lead (II) complex
Hence, the chemical equations are given above.
<span>: The empirical formula for the compound is C3H60 (see below)
CO2 is the only product containing C,
C produced = 145.0 mg CO2 x (1 g / 1000 mg) x (1 mole CO2 / 44.0 g CO2) x (1 mole C / 1 mole CO2) = 0.00330 moles C.
H2O is the only product containing H,
H produced = 59.38 mg H2O x (1 g / 1000 mg) x (1 mole H2O / 18.0 g H2O) x (2 moles H / 1 mole H2O) = 0.00660 moles H.
Oxygen is in both and the unknown reacts with oxygen(in the air)
0.00330 moles C x (12.0 g C / 1 mole C) = 0.0396 g C = 39.6 mg C
0.00660 moles H x (1.01 g H / 1 mole H) = 0.00667 g H = 6.7 mg H
Because the unknown weighed 63.8 mg and consists off justC, H, and O, then
mass O = g unknown - g C - g H = 63.8 mg - 39.6 mg - 6.7 mg = 17.5 mg = 0.0175 g
0.0175 g O x (1 mole O / 16.0 g O) = 0.00109 moles O
The mole ratio of C:H:O is:
C = 0.00330
H = 0.00660
O = 0.00109
Divide by the smallest you get:
C = 0.00330 / 0.00109 = 3.03
H = 0.00660 / 0.00109 = 6.06
O = 0.00109 / 0.00109 = 1.00</span>
Answer:
0.717 M LiOH
Explanation:
(Step 1)
Calculate the moles of H₃PO₄ using the molarity equation.
29.15 mL / 1,000 = 0.02915 L
Molarity = moles / volume (L)
0.205 M = moles / 0.02915 L
0.00598 = moles
(Step 2)
Convert moles H₃PO₄ to moles LiOH using the mole-to-mole ratio from reaction coefficients.
1 H₃PO₄ + 3 LiOH -----> Li₃PO₄ + 3 H₂O
^ ^
0.00598 moles H₃PO₄ 3 moles LiOH
------------------------------------ x -------------------------- = 0.0179 moles LiOH
1 mole H₃PO₄
(Step 3)
Calculate the molarity of LiOH using the molarity equation.
25.0 mL / 1,000 = 0.0250 L
Molarity = moles / volume (L)
Molarity = 0.0179 moles / 0.0250 L
Molarity = 0.717 M
3 elements
Rubidium
Manganese
Oxygen
Hope this helped☺️
