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3 years ago

Write the balanced chemical equation for each of these reactions. Include phases.

Chemistry

1 answer:

Ket [755]3 years ago

4 0

Answer: The chemical equations are given below.

Explanation:

For 1:

The chemical equation for the reaction of lead nitrate and sodium hydroxide follows:

$Pb(NO_3)_2(aq.)+2NaOH(aq.)\rightarrow Pb(OH)_2(s)+2NaNO_3(aq.)$

By Stoichiometry of the reaction:

1 mole of aqueous solution of lead nitrate reacts with 2 moles of aqueous solution of sodium hydroxide to produce 1 mole of solid lead hydroxide and 2 moles of aqueous solution of sodium nitrate.

For 2:

The chemical equation for the reaction of lead hydroxide and hydroxide ions follows:

$Pb(OH)_2(s)+2OH^-(aq.)\rightarrow [Pb(OH)_4]^{2-}(aq.)$

By Stoichiometry of the reaction:

1 mole of lead hydroxide reacts with 2 moles of aqueous solution of hydroxide ions to produce 1 mole of aqueous solution of tetra hydroxy lead (II) complex

Hence, the chemical equations are given above.

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3 years ago

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3 years ago

You are performing an experiment in a lab to attempt a new method of producing pure elements from

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Answer:

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Explanation:

Since, the atomic mass of the elements is a characteristic property of the elements, you can use the data given, number of moles and mass in grams of the product, to calculate the atomic mass of the product, and then compare with the atomic masses of the elements (information foun in any periodic table).

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3 years ago

A certain reaction has an enthalpy of Δ=44 kJ and an activation energy of a=61 kJ. What is the activation energy of the reverse

avanturin [10]

Answer:

E = 17 kJ

Explanation:

The enthalpy of the reaction is:

$\Delta H = E_{p} - E_{r}$

Where:

Ep: is the energy of the products

Er: is the energy of the reactants

Similarly, the enthalpy of the reaction is related to the activation energy forward ( $E_{F}$ ) and to the activation energy reverse ( $E_{R}$ ) as follows:

$\Delta H = E_{F} - E_{R}$

Having that ΔH = 44 kJ and $E_{F}$ = 61 kJ, the activation energy of the reverse reaction is:

$E_{R} = E_{F} - \Delta H = 61 kJ - 44 kJ = 17 kJ$

Therefore, the activation energy of the reverse reaction is 17 kJ.

I hope it helps you!

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3 years ago