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3 years ago

What is the answer to the question ?

Physics

1 answer:

nadya68 [22]3 years ago

5 0

0.11m/s

Explanation:

avg. velocity = total displacement/ total time

total displacement = 2.55 - 1.09

= 1.46

total time taken = 12.8s

avg velocity = 1.46/12.8

=0.11

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The level of mercury falls in a barometer<br>while taking it to a mountain.

Alexxandr [17]

Answer:

This is due to a relative decrease in atmospheric pressure in high places.

Explanation:

Given that atmospheric pressure decreases at the higher point or ground, this reduced atmospheric pressure, however, will be unable to contain the Mercury in the barometer tube.

Therefore, at the top of the mountain where the air pressure is low, the barometer reading ultimately goes down.

Hence, the level of mercury falls in a barometer while taking it to a mountain "due to a relative decrease in atmospheric pressure in high places."

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2 years ago

How many grams of CO2 are in 10 mol of the compound?

Zepler [3.9K]

For our problem, this means that one mole of CO2 has a mass of 44.01 grams. So 22 grams divided by 44.01 grams is roughly 0.5 moles of CO2.

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3 years ago

Help when u can! I feel like it's C, but I just want to make sure before I submit the test.

Marat540 [252]

(D)

Explanation:

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2 years ago

Match the choices below to the correct description. Drag the terms on the left to the appropriate blanks on the right. ResetHelp

Andreas93 [3]

Answer: hello the terms are missing but I have provided the answer ( the terms and matched them properly

answer :

P WAVES
S WAVES
L WAVES
R WAVES

Explanation:

This body wave is a compressional wave : P WAVES

This body wave is a shear wave : S WAVES

This surface wave moves from side to side : L WAVES

This surface wave moves up and down. : R WAVES

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3 years ago

A car of mass 1600 kg traveling at 27.0 m/s is at the foot of a hill that rises vertically 135 m after travelling a distance of

Zarrin [17]

Answer:

Neglecting any frictional losses, the average power delivered by the car's engine is 10565 W

Explanation:

The energy conservation law indicates that the energy must be the same at the bottom of the hill and at the top of the hill.

The energy at the bottom is only the Kinect energy (K_1) of the car in motion, but in the top, the energy is the sum of its Kinect energy (K_2), potential energy (P) and the work (W) done by the engine.

$K_1 = K_2 + P + W$

then, the work done by the engine is:

$W = K_1 - K_2 - P$

The formulas for the Kinetic and potential energy are:

$K=\frac{1}{2}mV^2\\P=mgh$

where, m is the mass of the car, V the velocity, g the gravity and h is the elevation of the hill.

Using the formulas:

$W=\frac{1}{2}mV_1^2-\frac{1}{2}mV_2^2-mgh$

Replacing the values:

$W=\frac{1}{2}(1600Kg)(27m/s)^2-\frac{1}{2}(1600Kg)(14m/s)^2-(1600Kg)(9.8m/s^2)(135m)\\W=-1690400 J$

The negative of this value indicates the direction of the work done, but for the problem, you only care about the magnitude, so the power is W=1690400 J. Now, the power is equal to work/time so you need to find the time the car took to get to the top of the hill.

The average speed of the car is (27+14)/2=20m/s, and t=d/v so the time is:

$t=\frac{3200m}{20m/s}=160s$

the power delivered by the car's engine was:

$power=\frac{work}{time}=\frac{1690400J}{160s}=10565W$

8 0

3 years ago