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4 years ago

14

What tool could help a biologist study the movements of cells? digital camera with a zoom lens a satellite with a digital camera

a television with a remote control a microscope with a video camera

2 answers:

Annette [7]4 years ago

4 0

I think your answer would be (D) microscope with a video camera
Hope i helped!

Mandarinka [93]4 years ago

4 0

Answer:

a microscope with a video camera

Explanation:

gg Dva style

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A store owner has 11 baskets of mangoes for sale at k8.26.How much will he receive in total when he sells them

Grace [21]

11*2.86 which is 31.46
Hope this helps

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4 years ago

Read 2 more answers

One of the dangers of tornados and hurricanes is the rapid drop in air pressurethat is associated with such storms. Assume that

Oksi-84 [34.3K]

Answer:

The net outward force is exerted on a square window of the house is $4.5930\times10^{4}\ N$ .

Explanation:

Given that,

Pressure = 1.02 atm

External air pressure = 0.910 atm

Distance = 2.03 m

We need to calculate the net outward force

Using formula of force

$F= PA$

Where, P = pressure

F = force

A = area

Put the value into the formula

$F=(1.02-0.910)\times101325\times(2.03)^2$

$F=4.5930\times10^{4}\ N$

Hence, The net outward force is exerted on a square window of the house is $4.5930\times10^{4}\ N$ .

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4 years ago

Which of Earth's compounds makes the planet unique because it can exist in solid, liquid, or gaseous states under normal conditi

lukranit [14]

That's the description of WATER.

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3 years ago

5. What is the frequency of a sound wave when the speed of the sound is 340 m/s and has a wavelength of 1.21 m?

LekaFEV [45]

Explanation:

v = f × /\

340 = 1.21f

f = 280.99Hz

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3 years ago

There are two balloons of charges +3.37 x 10-6 C and –8.21 x 10-6 C. The distance between the two balloons is 2.00 m. Determine

andrew-mc [135]

F = 0.06N. Since the charges has different signs the force of atraction between them is 0.06N.

In order to solve this exercise we have to use Coulomb's Law equation which says that the magnitude of each of the electric forces with which two point charges at rest interact is directly proportional to the product of the magnitude of both charges and inversely proportional to the square of the distance that separates them. Given by the equation:

$F = k\frac{|q_{1}q_{2}|}{d^{2}}$ . Where k is the Coulomb's Constant $k = 9x10^{9}\frac{Nm^{2} }{C^{2} }$ , q1 and q2 are the charges value in Coulomb (C), and d is the distance between charges in meters (m).

There are two balloons of charges +3.37 x 10-6 C and –8.21 x 10-6 C. The distance between the two balloons is 2.00 m. Calculate the force between the two ballons.

$F = 9x10^{9}\frac{Nm^{2} }{C^{2} } \frac{|(3.37x10^{-6}C)(-8.21x10^{-6}C)|}{(2.00m)^{2}}\\F = 9x10^{9}\frac{Nm^{2} }{C^{2} } \frac{|-2.77x10^{-11}C^{2} )|}{4.00m^{2}}\\F = 9x10^{9}\frac{Nm^{2} }{C^{2} }(6.92x10^{-12})\frac{C^{2} }{m^{2}}\\F = 0.06N$

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3 years ago