All categories

3 years ago

Determine the mass of fuel required for the expected energy consumption in the United States for the next 10 years:

Physics

1 answer:

alexandr1967 [171]3 years ago

8 0

Answer:

(This will depend on the type of fuel, I will assume that the fuel is petrol)

First, let's find the expected energy consumption in the US for the next 10 years.

We know that in one year, a person consumes 3.5*10^11 joules.

There are 310,000,00 people on the US

Then the total consumption in one year is:

310,000,000*3.5*10^11 joules = 1.085*10^20 J

In 10 years the consumption is 10 times the consumption of a single year, then the expected energy consumption in the US for the next 10 years is:

10*1.085*10^20 J = 1.085*10^21 J

Now let's find the mass of fuel required.

We know that a liter of petrol has 31,536,000 joules of energy,

And a liter of petrol weights 0.75 kg

To find the number of liters of petrol that we need, we need to find the quotient between the expected energy consumption in the next 10 years and the energy of a single liter of petrol, this is:

N = (1.085*10^20 J)/(31,536,000 j) = 3.44*10^13

We will need 3.44*10^13 liters of petrol.

And the total mass of petrol will be:

M = 3.44*10^13*0.75 kg = 2.58*10^13 kg of fuel.

You might be interested in

Zero, a hypothetical planet, has a mass of 5.3 x 1023 kg, a radius of 3.3 x 106 m, and no atmosphere. A 10 kg space probe is to

Andrej [43]

(a) $3.1\cdot 10^7 J$

The total mechanical energy of the space probe must be constant, so we can write:

$E_i = E_f\\K_i + U_i = K_f + U_f$ (1)

where

$K_i$ is the kinetic energy at the surface, when the probe is launched

$U_i$ is the gravitational potential energy at the surface

$K_f$ is the final kinetic energy of the probe

$U_i$ is the final gravitational potential energy

Here we have

$K_i = 5.0 \cdot 10^7 J$

at the surface, $R=3.3\cdot 10^6 m$ (radius of the planet), $M=5.3\cdot 10^{23}kg$ (mass of the planet) and m=10 kg (mass of the probe), so the initial gravitational potential energy is

$U_i=-G\frac{mM}{R}=-(6.67\cdot 10^{-11})\frac{(10 kg)(5.3\cdot 10^{23}kg)}{3.3\cdot 10^6 m}=-1.07\cdot 10^8 J$

At the final point, the distance of the probe from the centre of Zero is

$r=4.0\cdot 10^6 m$

so the final potential energy is

$U_f=-G\frac{mM}{r}=-(6.67\cdot 10^{-11})\frac{(10 kg)(5.3\cdot 10^{23}kg)}{4.0\cdot 10^6 m}=-8.8\cdot 10^7 J$

So now we can use eq.(1) to find the final kinetic energy:

$K_f = K_i + U_i - U_f = 5.0\cdot 10^7 J+(-1.07\cdot 10^8 J)-(-8.8\cdot 10^7 J)=3.1\cdot 10^7 J$

(b) $6.3\cdot 10^7 J$

The probe reaches a maximum distance of

$r=8.0\cdot 10^6 m$

which means that at that point, the kinetic energy is zero: (the probe speed has become zero):

$K_f = 0$

At that point, the gravitational potential energy is

$U_f=-G\frac{mM}{r}=-(6.67\cdot 10^{-11})\frac{(10 kg)(5.3\cdot 10^{23}kg)}{8.0\cdot 10^6 m}=-4.4\cdot 10^7 J$

So now we can use eq.(1) to find the initial kinetic energy:

$K_i = K_f + U_f - U_i = 0+(-4.4\cdot 10^7 J)-(-1.07\cdot 10^8 J)=6.3\cdot 10^7 J$

3 0

3 years ago

Read this quotation:

Brums [2.3K]

Answer:

the Princess in "St. George and the Dragon"

4 0

3 years ago

Read 2 more answers

A 1.4 kg block slides across a rough surface such that it slows down with an acceleration of 1.25 m/s(squared). What is the coef

tino4ka555 [31]

F = ma

where 

F = frictional force 
m = mass of the block = 1.4 kg (given) 
a = acceleration of the block = 1.25 m/sec^2 (given) 

Substituting values, 

F = (1.4)(1.25) 

F = 1.75 N 

By definition, 

F = (mu)(Normal force) 

where 

mu = coefficient of friction 
Normal force = mg = 1.4*9.8 = 13.72 

Again, substituting appropriate values, 

1.75 = mu(13.72) 

mu = 0.128

5 0

3 years ago

What is the most commmon injury in the United states

Bess [88]

Home injury’s or at home falls

5 0

3 years ago

The ___________ is the solid Earth, composed principally of rock (by which we mean any naturally formed, nonliving, firm coheren

irina1246 [14]

Answer:

Geosphere

Explanation:

The Geosphere is the solid Earth,composed principally of rock (by which we mean any naturally formed, nonliving, firm coherent aggregate mass of solid matter that constitutes part of a planet).

The geosphere is defined to be that component of the Earth system involving the inside of the Earth, rocks and materials, minerals, land forms and the mechanisms that shape the surface of the Earth. Contrary to Christopher Columbus, the Earth is not in itself a perfect sphere.

6 0

4 years ago