If 22.5 mol of an ideal gas occupies 30.5 L at 447 K, what is the pressure of the gas?

Chemistry

1 answer:

Fantom [35]3 years ago

8 0

Answer:

P = 27.07 atm

Explanation:

Given that,

The number of moles, n = 22.5 mol

Volume, V = 30.5 L

Temperature, T = 447 K

We need to find the pressure of the gas. The ideal gas law is as follows :

$PV=nRT\\\\P=\dfrac{nRT}{V}$

R = 0.0821 L-atm/mol-K

Put all the values,

$P=\dfrac{22.5\times 0.0821\times 447}{30.5}\\\\P=27.07\ L$

So, the pressure of the gas is 27.07 atm.

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