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bonufazy [111]
3 years ago
11

Which of the following series describe the correct pathway of oxygen in the breathing system?

Chemistry
1 answer:
SashulF [63]3 years ago
8 0

Answer:

Respiratory System:

Pathway of air: nasal cavities (or oral cavity) > pharynx > trachea > primary bronchi (right & left) > secondary bronchi > tertiary bronchi > bronchioles > alveoli (site of gas exchange)

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Which of the following statements is true based on the propositions of the kinetic molecular theory?
Delvig [45]
The answer is 4.
Gases have low densities, because of the increased space between hight-energy particles.
6 0
3 years ago
Read 2 more answers
Iron iii chloride ammonium hydroxide balanced equation, complete ionic equation, net ionic equation
Vladimir [108]
Iron III Chloride has a chemical formula of FeCl₃, while ammonium hydroxide has a chemical formula of NH₄OH. 

The <em>balanced equation</em> would be:

FeCl₃ (aq) + 3 NH₄OH (aq) → Fe(OH)₃ (s) + 3 NH₄Cl (aq)
The precipitate is Fe(OH)₃ or iron iii hydroxide.

To find the <em>complete ionic equation</em>, dissociate the compounds in aqueous phases into their ionic forms:

Fe³⁺ + Cl⁻ + NH₄⁺ + 3 OH⁻ -->  Fe(OH)₃(s) + NH₄⁺ + Cl⁻ 

To find the <em>net ionic equation</em>, cancel out like ions that appear both in the reactant and product side:

Fe³⁺ +  3 OH⁻ -->  Fe(OH)₃


4 0
3 years ago
If a substance has a half life of 58 years and starts with 500 g radioactive, how much remains radioactive after 30 years?
Vilka [71]

Answer:

A = 349 g.

Explanation:

Hello there!

In this case, since the radioactive decay kinetic model is based on the first-order kinetics whose integrated rate law is:

A=Ao*exp(-kt)

We can firstly calculate the rate constant given the half-life as shown below:

k=\frac{ln(2)}{t_{1/2}} =\frac{ln(2)}{58year}=0.012year^{-1}

Therefore, we can next plug in the rate constant, elapsed time and initial mass of the radioactive to obtain:

A=500g*exp(-0.012year^{-1} *30year)\\\\A=349g

Regards!

5 0
3 years ago
OA) can never be seen from Earth
Paraphin [41]

Explanation:

what are you talking about tho

5 0
2 years ago
Use the table to calculate ΔH°rnx for the following reaction
alexdok [17]

Answer:

The answer to your question is ΔH° rxn = -1343.9 kJ/mol

Explanation:

                       P₄O₆ (s)  +  2 O₂ (g)   ⇒  P₄O₁₀

ΔH°rxn = ?

Formula

ΔH°rxn = ∑H° products - ∑H° reactants

H° P₄O₆ = -1640.1 kJ/mol

H° O₂ = 0 kJ/mol

H° P₄O₁₀ = -2984 kJ/mol

-Substitution

ΔH° rxn = (-2984) - (-1640.1) - (0)

-Simplification

ΔH° rxn = -2984 + 1640.1

ΔH° rxn = -1343.9 kJ/mol

7 0
2 years ago
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