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2 years ago

Pls answer the question

Mathematics

1 answer:

AURORKA [14]2 years ago

5 0

Answer:

the answer is 35

Step-by-step explanation:

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QUESTION 2 Simplify the following a5×a7

Kryger [21]

Answer:

$a^{12}$

Step-by-step explanation:

Identity Used : $a^x \times a^y = a^{x+ y}$

$a^5 \times a^7 = a^{5 + 7} = a^{12}$

6 0

3 years ago

Read 2 more answers

Explain how you could use the construction tool or a compass and straightedge to create a line segment that is twice as long.

ycow [4]

Answer: Use a compass to measure the length of AB. Draw an arc from point B (or point A) with that distance. Extend line AB through that arc and label the intersection as point C. AC is twice the length of AB.

3 0

3 years ago

Solve the inequality. 5/6t - 3≥3t + 6

Papessa [141]

Answer:

t ≤ $-\frac{54}{13}$

Step-by-step explanation:

$\frac{5}{6}$ t−3−3t≥3t+6−3t

$-\frac{13}{6}$ t−3≥6

- $\frac{13}{6}t$ −3+3≥6+3

$\frac{13}{6}$ t≥9

$-\frac{6}{13}$ ( $-\frac{13}{6}$ t) ≥ $-\frac{6}{13}$ (9)

t ≤ $-\frac{54}{13}$

6 0

2 years ago

Answer as soon as possible please !

creativ13 [48]

Answer:

Step-by-step explanation:

4/3 = x/45

45/3=15

15*4=60

x=60

4 0

3 years ago

Make a histogram, using a bin width of ten, to display the bowling scores for these 31 players: 87, 104, 79, 94, 117, 82, 72, 11

slavikrds [6]

Step-by-step explanation:

Using R, I used the following code to create a histogram:

bowling.scores <- c(87, 104, 79, 94, 117, 82, 72, 116, 105, 95, 88, 93, 109, 119, 75,

103, 112, 97, 73, 85, 91, 86, 102, 99, 106, 84, 98, 83, 81, 96, 92)

data.frame(bowling.scores)

ggplot(data.frame(bowling.scores), aes(x=bowling.scores)) +

xlim(c(70, 120)) +

scale_y_continuous(breaks = seq(0, 10, by=1), "Frequency") +

geom_histogram(breaks=seq(70, 120, by=10), color="black", fill="grey60") +

labs(title="Histogram of Bowling Scores", x="Bowling Scores", y="Frequency")

7 0

3 years ago