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Molodets [167]
3 years ago
14

The area of a rectangular field is 99m2. The length of one side is

Mathematics
2 answers:
goldfiish [28.3K]3 years ago
5 0

Answer:

40 m

Step-by-step explanation:

The length of another side

= 99÷11

= 9 m

The perimeter of the field

= 9×2 + 11×2

= 40 m

Volgvan3 years ago
4 0

Answer:

40 m

Step-by-step explanation:

Hi there!

<u>What we know:</u>

  • The field is rectangular
  • A = 99 m²
  • Length of one side = 11 m

<u>1) Find the length of the other side</u>

Plug all the given information into the area formula for a rectangle:

A=lw where A is the area, l is the length and w is the width

99=11w

Divide both sides by 11 to isolate w

\frac{99}{11} = \frac{11w}{11} \\9=w

Therefore, the width of the field is 9 m.

<u>2) Find the perimeter of the field</u>

P=2(l+w) where l is the length and w is the width

Plug in the length (11 m) and the width (9 m)

P=2(11+9)\\P=2(20)\\P=40

Therefore, the perimeter of the field is 40 m.

I hope this helps!

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Let XXX and YYY be the following sets: X = \{9, 25\}X={9,25}X, equals, left brace, 9, comma, 25, right brace Y = \{1, 4, 9,16,25
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Arvin has $10000 to invest. He invests part in a term deposit paying 5%/year, and the remainder in Canada savings bonds paying 3
Delicious77 [7]

Answer:

$4,562.5

Step-by-step explanation:

The amount Arvin has to invest, P = $10,000

The interest paid on the investment in the term deposit = 5%/year

The interest paid om the investment in Canada savings bonds = 3.4%/year

The amount Arvin earned at the of the year as simple interest, A = $413

Let, <em>x</em>, represent the amount Arvin invested in the term deposit and let, <em>y</em>,<em> </em>represent the amount he invested in Canada savings bonds, we can get the following system of equations

x + y = 10,000...(1)

0.05·x + 0.034·y = 413...(2)

Making <em>y</em> the subject of equation (1) and substituting the value in equation (2), we get;

From equation (1), we get, y = 10,000 - x

Plugging the above value of <em>y</em> in equation (2) gives;

0.05·x + 0.034 × (10,000 - x) = 413

∴ 0.05·x - 0.034·x + 340 = 413

x = (413 - 340)/(0.05 - 0.034) = 4,562.5

Therefore, the amount Arvin invested in the term deposit at 5%, x = $4,562.5

<em>(y = 10,000 - x</em>

<em>∴ y = 10,000 - 4,562.5 = 5,437.5</em>

<em>The amount Arvin invested in Canada savings bonds, y = $5,437.5.)</em>

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