Answer:
I will answer this in English, we can translate it to:
Why if you charge a mate by an amount of time you are not doing work?
This happens because work is defined as the displacement done by a force:
W = d*F
where W is work, d is the distance, and F is the force.
This means that the amount of time that you are charging your mate does not affect the mechanical work, the only time that you are doing work is when you are lifting him.
A complete loop/ring of wire
Answer:
The current is 
Explanation:
From the question we are told that
The radius is 
The current density is 
The distance we are considering is 
Generally current density is mathematically represented as

Where A is the cross-sectional area represented as

=> 
=> 
Now the change in current per unit length is mathematically evaluated as

Now to obtain the current (in A) through the inner section of the wire from the center to r = 0.5R we integrate dI from the 0 (center) to point 0.5R as follows


![I = 2\pi *(9.0*10^{6}) [\frac{r^4}{4} ] | \left 0.001585} \atop 0}} \right.](https://tex.z-dn.net/?f=I%20%20%3D%202%5Cpi%20%2A%289.0%2A10%5E%7B6%7D%29%20%5B%5Cfrac%7Br%5E4%7D%7B4%7D%20%5D%20%20%7C%20%5Cleft%20%20%20%200.001585%7D%20%5Catop%200%7D%7D%20%5Cright.)
![I = 2\pi *(9.0*10^{6}) [ \frac{0.001585^4}{4} ]](https://tex.z-dn.net/?f=I%20%20%3D%202%5Cpi%20%2A%289.0%2A10%5E%7B6%7D%29%20%5B%20%5Cfrac%7B0.001585%5E4%7D%7B4%7D%20%5D)
substituting values
![I = 2 * 3.142 * 9.00 *10^6 * [ \frac{0.001585^4}{4} ]](https://tex.z-dn.net/?f=I%20%20%3D%202%20%2A%20%203.142%20%20%2A%20%209.00%20%2A10%5E6%20%2A%20%20%20%5B%20%5Cfrac%7B0.001585%5E4%7D%7B4%7D%20%5D)

Answer:
0.2 – 4.6 seconds increasing speed in positive direction
4.6 - 7.8 seconds decelerating speed in a positive direction
8 - 17.2 seconds accelerating speed in a negative direction
Explanation:
**Plato** **Edmentum**n~ this question is pretty open ended, so its hard to get it wrong honestly, good luck <3 ~
This question is asking: Why does gravity occur? why will your notebook get pulled towards you?