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blsea [12.9K]
3 years ago
5

A roller coaster is released from the top of a track that is 125 m high. Find the rollar coaster speed when it reaches ground le

vel.​
Physics
1 answer:
astra-53 [7]3 years ago
6 0

Explanation:

A roller coaster is released from the top of a track that is 125 m high. Find the roller coaster speed when it reaches ground level. 75. A 1500 kg car, moving at a speed of 20 m/s comes to a halt. How much work was done .

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Fill in the blanks about Newton’s First Law of Motion:
Afina-wow [57]

Objects want to continue doing what they’re doing because they are “lazy.” This is called law of inertia.

Newton's first law of motion states that an object at rest or uniform motion in a straight line will continue in that state unless it is being acted upon by an external force. This law is also called the law of inertia because it depends on mass.

<em>From the given question, we can </em><em>fill gaps </em><em>as follows;</em>

Objects want to continue doing what they’re doing because they are “lazy.” This is called law of inertia.

Learn more about Newton's first law of motion here: brainly.com/question/10454047

6 0
2 years ago
The valve in the exit pipe is closed . The density of water is 1000kg / m and the gravitational force on free fall of water is 1
Stels [109]

Answer:

300000

Explanation:

p=30x10x1000=30000pascal

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2 years ago
Read 2 more answers
A uniform disk has a moment of inertia that is (1/2)MR2. A uniform disk of mass 13 kg, thickness 0.3 m, and radius 0.2 m is loca
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The angular momentum of an object is equal to the product of its moment of inertia and angular velocity.
L = Iω
I = 1/2 MR²
I = 1/2 x 13 x (0.2)
I = 1.3

ω = 2π/t
ω = 2π/0.3
ω = 20.9

L = 1.3 x 20.9
= 27.2 kgm²/s
6 0
3 years ago
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A harmonic force of maximum value 25 N and frequency of 180 cycles&gt;min acts on a machine of 25 kg mass. Design a support syst
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Answer:

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3 0
3 years ago
A 1.0 meter long rod is held horizontally in the east-west direction on a distant planet and is dropped from a height of 1.23 m.
enyata [817]

Answer:

The induced emf between two end is 34.02 \times 10^{-5} V

Explanation:

Given:

Length of rod l = 1 m

Height h = 1.23 m

Magnetic field B = 6.93 \times 10^{-5} T

For finding induced emf,

  \epsilon = Blv

Where v = velocity of rod,

For finding the velocity of rod.

From kinematics equation,

 v^{2} = v_{o} ^{2} + 2gh

Where v_{o} = initial velocity, g = 9.8 \frac{m}{s^{2} }

   v = \sqrt{2gh}

   v = \sqrt{2 \times 9.8 \times 1.23}

   v = 4.91 \frac{m}{s}

Put the velocity in above equation,

   \epsilon = 6.93 \times 10^{-5} \times 1 \times 4.91

   \epsilon = 34.02 \times 10^{-5} V

Therefore, the induced emf between two end is 34.02 \times 10^{-5} V

6 0
3 years ago
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