Moles of Oxygen= 2.8075 moles
<h3>Further explanation</h3>
Given
29.2 grams of acetylene
Required
moles of Oxygen
Solution
Reaction(Combustion of Acetylene) :
2 C₂H₂ (g) + 5 O₂ (g) ⇒ 4CO₂ (g) + 2H₂O (g)
Mol of Acetylene :
= mass : MW Acetylene
= 29.2 g : 26 g/mol
= 1.123
From equation, mol ratio of Acetylene(C₂H₂) : O₂ = 2 : 5, so mol O₂ :
= 5/2 x mol C₂H₂
= 5/2 x 1.123
= 2.8075 moles
Answer:
87.5198
Explanation:
(43.65 * 87.05) + (48.25 * 87.93) + (8.11 * 87.50) = 8751.98
8751.98 / 100 = 87.5198
Answer:
URGENT PLEASE HELP!! Earth science!!
What stages of development are represented by the Group 2 and Group 3 stars? Describe these
groups in terms of their relative age, size, brightness, and temperature.
Answer:
first-order reaction is 0.300 s–1 at 400 °C.. ... (in seconds) would it take for the concentration of A to decrease from 0.900 M
Explanation:
yep thats all i know
Answer:
a. Zinc is the limiting reactant.
b. 
c. 
Explanation:
Hello there!
a. In this case, when zinc metal reacts with bromine, the following chemical reaction takes place:

Thus, since zinc and bromine react in a 1:1 mole ratio, we can compute their reacting moles to identify the limiting reactant:

Thus, since zinc has the fewest moles we infer it is the limiting reactant.
b. Here, we compute the grams of zinc bromide via both reactants:

That is why zinc is the limiting reactant, as it yields the fewest moles of zinc bromide product.
c. Here, since just 0.722 mol of bromine would react, we compute the corresponding mass:

Thus, the leftover of bromine is:

Best regards!