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3 years ago

Which of these elements could be formed at the anode when a molten salt is electrolysed?

Chemistry

2 answers:

snow_lady [41]3 years ago

8 0

Hm mybeeeee just mybe it’s c

Oksana_A [137]3 years ago

6 0

Answer: A-Copper.

Explanation:

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The equilibrium constant for the reaction AgBr(s) Picture Ag+(aq) + Br− (aq) is the solubility product constant, Ksp = 7.7 × 10−

barxatty [35]

Answer:

The reaction will be non spontaneous at these concentrations.

Explanation:

$AgBr(s)\rightarrow Ag^+(aq) + Br^- (aq)$

Expression for an equilibrium constant $K_c$ :

$K_c=\frac{[Ag^+][Br^-]}{[AgCl]}=\frac{[Ag^+][Br^-]}{1}=[Ag^+][Br^-]$

Solubility product of the reaction:

$K_{sp}=[Ag^+][Br^-]=K_c=7.7\times 10^{-13}$

Reaction between Gibb's free energy and equilibrium constant if given as:

$\Delta G^o=-2.303\times R\times T\times \log K_c$

$\Delta G^o=-2.303\times R\times T\times \log K_{sp}$

$\Delta G^o=-2.303\times 8.314 J/K mol\times 298 K\times \log[7.7\times 10^{-13}]$

$\Delta G^o=69,117.84 J/mol=69.117 kJ/mol$

Gibb's free energy when concentration $[Ag^+] = 1.0\times 10^{-2} M$ and $[Br^-] = 1.0\times 10^{-3} M$

Reaction quotient of an equilibrium = Q

$Q=[Ag^+][Br^-]=1.0\times 10^{-2} M\times 1.0\times 10^{-3} M=1.0\times 10^{-5}$

$\Delta G=\Delta G^o+(2.303\times R\times T\times \log Q)$

$\Delta G=69.117 kJ/mol+(2.303\times 8.314 Joule/mol K\times 298 K\times \log[1.0\times 10^{-5}])$

$\Delta G=40.588 kJ/mol$

For reaction to spontaneous reaction: $\Delta G$ .
For reaction to non spontaneous reaction: $\Delta G>0$ .

Since ,the value of Gibbs free energy is greater than zero which means reaction will be non spontaneous at these concentrations

5 0

3 years ago

True or False: Cohesion is the attraction between particles of the same<br> substance

RideAnS [48]

Answer: True

Explanation:

4 0

3 years ago

Chemistry student needs 15.0 g of painting for an experiment by consulting the CRC handbook of chemistry and physiology the stud

nalin [4]

Answer:

v = 23.96 cm³

Explanation:

Given data:

Mass = 15.0 g

Density = 0.626 g/cm³

Volume = ?

Solution:

Formula:

D=m/v

D= density

m=mass

V=volume

Now we will put the values in formula:

d = m/v

v = m/d

v = 15 g / 0.626 g/cm³

v = 23.96 cm³

8 0

3 years ago

A 5.5 sample of battery acid contains 490.0g of sulfuric acid H2SO4

prohojiy [21]

$n = \frac{m}{mw} \\ n = \frac{490}{98} \\ n = 5 \: mol$

5 0

3 years ago

Is warm water or cold water more dense

diamong [38]

Cold water is denser

8 0

3 years ago

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