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Travka [436]
3 years ago
5

A 4kg box is pressed into a spring. The spring constant k=220N/m. The box is released at the bottom of a frictionless ramp and r

ises to a height of y= 0.75m as shown below.
How far was the spring compressed? In meters.​
Physics
2 answers:
AVprozaik [17]3 years ago
8 0

Answer:

Explanation:

The stored elastic energy in the spring helps the box to rise to a height of .75 m

So stored elastic energy = potential energy attained

1/2 k d² = mgh , k is spring constant , d is compression in spring , m is mass of box , h is height attained .

Putting the values

.5 x 220 x d² = 4 x 9.8 x .75

d² = .2673

d = .517 m

51.7 cm .

aleksley [76]3 years ago
4 0

Answer: It’s 0.52 m

Explanation: Khan

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          u = [-5633.8 ±√(5633.8 2 + 4 48.03)] / 2

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