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Travka [436]
3 years ago
5

A 4kg box is pressed into a spring. The spring constant k=220N/m. The box is released at the bottom of a frictionless ramp and r

ises to a height of y= 0.75m as shown below.
How far was the spring compressed? In meters.​
Physics
2 answers:
AVprozaik [17]3 years ago
8 0

Answer:

Explanation:

The stored elastic energy in the spring helps the box to rise to a height of .75 m

So stored elastic energy = potential energy attained

1/2 k d² = mgh , k is spring constant , d is compression in spring , m is mass of box , h is height attained .

Putting the values

.5 x 220 x d² = 4 x 9.8 x .75

d² = .2673

d = .517 m

51.7 cm .

aleksley [76]3 years ago
4 0

Answer: It’s 0.52 m

Explanation: Khan

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arlik [135]

Answer:

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a = 1260.3 m/s^2

Part b)

Direction = upwards

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Part a)

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a = \frac{6.26 - (-8.86)}{12.0 \times 10^{-3}}

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Part B)

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7 0
3 years ago
An object is floating in equilibrium on the surface of a liquid. The object is then removed and placed in another container, fil
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Answer:

The fraction of its volume inside liquid  is increased .

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In the second case , when the body is dipped into liquid of lesser density , in order to balance the weight of body , more volume of liquid will be displaced so that weight of displaced liquid becomes equal to object's weight . So the body floats with greater depth inside liquid . The fraction of its volume inside liquid  is increased .

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A ball is shot at an angle of 45 degrees into the air with initial velocity of 46 ft/sec. Assuming no air resistance, how high d
mestny [16]

Answer:

5.02 m

Explanation:

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