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lakkis [162]
3 years ago
12

What bet force is required to stop a 2250 kg car if the decelerates at a rate of -4.3 m/s^2 please answer fast

Physics
1 answer:
sweet-ann [11.9K]3 years ago
8 0

Answer:

Force = Mass × Acceleration

{ \tt{force = 2250 \times  4.3}} \\  = { \tt{9675 \: newtons}}

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This is 100 points. When i find out how i will put the first person to answer as brainiest.
grin007 [14]

Answer:

Thank you so much! Have a great day!

3 0
3 years ago
A pilot drops a package from a plane flying horizontally at a constant speed. Neglecting air resistance, when the package hits t
Dovator [93]

Answer:

The location of helicopter is behind the packet.

Explanation:

As the packet also have same horizontal velocity as same as the helicopter, and also it has some vertical velocity as it hits the ground.

The horizontal velocity remains same as there is no force in the horizontal direction. The vertical  velocity goes on increasing as acceleration due to gravity acts.

So, the helicopter is behind the packet.

7 0
3 years ago
The horizontal bar rises at a constant rate of three hundred mm/s causing peg P to ride in the quarter circular slot. When coord
SVETLANKA909090 [29]

Answer:

Explanation:

Given

Horizontal bar rises with 300 mm/s

Let us take the horizontal component of P be

P_x=rcos\theta

P_y=rsin\theta

where \thetais angle made by horizontal bar with x axis

Velocity at y=150 mm

150=300sin\theta

thus \theta =30^{\circ}

position ofP_x=rcos\theta =300\cdot cos30=300\times \frac{\sqrt{3}}{2}

P_x=259.80 mm

P=259.80\hat{i}+150\hat{j}

Velocity at this instant

u_x=-rsin\theta =300\times sin30=-150 mm/s

u_y=rcos\theta =300\times cos30=259.80 mm/s

4 0
3 years ago
URGENT
Gemiola [76]

Answer:

5.25 J

Explanation:

W = PE = (f)(x)

PE = 35N*0.15m

PE = 5.25 N*m

1 N*m = 1 J

PE = 5.25 J

7 0
3 years ago
A student releases a ball from a height of 100 cm above the ground. It bounces to a height of 80 cm. Answer the following questi
Zepler [3.9K]

if α = 90°, then the formula simplifies to: hmax = h + V₀² / (2 * g) and the time of flight is the longest. ...

if α = 45°, then the equation may be written as: ...

if α = 0°, then vertical velocity is equal to 0 (Vy = 0), and that's the case of horizontal projectile motion.

4 0
3 years ago
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