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Elena-2011 [213]
2 years ago
8

Which of these is NOT a physical property?

Physics
1 answer:
m_a_m_a [10]2 years ago
8 0
I believe the answer is chemical reactivity because: Characteristics such as melting point, boiling point, density, solubility, color, odor, etc. are physical properties.
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A 12 V battery is connected to a 1200 Ω resistor. How much current is flowing through the resistor?
Oduvanchick [21]

Explanation:

Use Ohm's law.

V = IR

12 V = I (1200 Ω)

I = 0.01 A

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In a velocity versus time graph, what does the slope of a line at any point indicate?
VladimirAG [237]
The acceleration and speed
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Hey everyone!
Soloha48 [4]
 8. In soft magnetic materials such as iron, what happens when an external magnetic field is removed? a. The domain alignment persists. b. The orientation of domains fluctuates. c. The material becomes a hard magnetic material. d. The orientation of domains changes, and the material returns to an unmagnetized state. 9. According to Lenz’s law, if the applied magnetic field changes, a. the induced field attempts to keep the total field strength constant. b. the induced field attempts to increase the total field strength. c. the induced field attempts to decrease the total field strength. d. the induced field attempts to oscillate about an equilibrium value. 10. The direction of the force on a current-carrying wire in an external magnetic field is a. perpendicular to the current only. b. perpendicular to the magnetic field only. c. perpendicular to the current and to the magnetic field. d. parallel to the current and to the magnetic field
6 0
3 years ago
Examples of a/an _______ observation are 37 m, 9.37 s, and 100 mph.
solniwko [45]

These are exaxmples of a quantitative observation.

Measuring is the expression of an observed quantity in a number with a relevant unit that can be compared with other values of the same quantity.

It is not limited to physical quantities, but extends to a quantitative description of the whole of reality. Measurements are usually quantitative observations, and their results are expressed in

  • numerical values, and
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Learn more about quantitative observations in brainly.com/question/12042148.

4 0
3 years ago
An object initially at rest experiences an acceleration of 1.90 ­m/s² for 6.60 s then travels at that constant velocity for anot
borishaifa [10]

Answer:

The magnitude of the object's average velocity is 9.74 m/s (9.80 m/s without any intermediate rounding).

Explanation:

Hi there!

The average velocity is calculated as the displacement of the object divided by the time it takes the object to do that displacement.

The displacement is calculated as the distance between the final position of the object and the initial position. <u>In this problem</u>, the displacement is equal to the traveled distance because the object travels only in one direction:

a.v = Δx/t

Where:

a.v = average velocity.

Δx = displacement = final position - initial position

t = time

So, let's find the distance traveled while the object was accelerating. For that, we will use this equation:

x = x0 + v0 · t + 1/2 · a · t²

Where:

x = position of the object at time t.

x0 = initial position.

v0 = initial velocity.

t = time.

a = acceleration.

In this case, since the object is initially at rest, v0 = 0. If we place the origin of the frame of reference at the point where the object starts moving, then x0 = 0. So, the equation of the position of the object after a time t will be:

x = 1/2 · a · t²

x = 1/2 · 1.90 m/s² · (6.60 s)²

x = 41.4 m

The object traveled 41.4 m during the first 6.60 s.

Now, let's find the rest of the traveled distance.

When the velocity is constant, a = 0. Then, the equation of position will be:

x = x0 + v · t

Let's place now the origin of the frame of reference at the point where the object starts traveling at constant velocity so that x0 = 0:

x = v · t

The velocity reached by the object during the acceleration phase is calculated as follows:

v = v0 + a · t   (v0 = 0 because the object started from rest)

v = 1.90 m/s² · 6.60 s

v = 12.5 m/s

Then, the distance traveled by the object at a constant velocity will be:

x = 12.5 m/s · 8.50 s

x = 106 m

The total traveled distance in 15.1 s is (106 m + 41.4 m) 147 m.

Then the displacement will be:

Δx = final position - initial position

Δx = 147 m - 0 = 147 m

and the average velocity will be:

a.v = Δx/t

a.v = 147 m / 15.1 s

a.v = 9.74 m/s

The magnitude of the object's average velocity is 9.74 m/s (9.80 m/s without any intermediate rounding).

8 0
3 years ago
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