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The velocity of B after elastic collision is 3.45m/s
This type of collision is an elastic collision and we can use a formula to solve this problem.
<h3>Elastic Collision</h3>The data given are;
- m1 = 281kg
- u1 = 2.82m/s
- m2 = 209kg
- u2 = -1.72m/s
- v1 = ?
Let's substitute the values into the equation.
From the calculation above, the final velocity of the car B after elastic collision is 3.45m/s.
Learn more about elastic collision here;
During the fall, all the initial potential energy of the rock
has converted into kinetic energy of motion
where h is the initial height of the rock, m its mass, and v its velocity just before hitting the water. So, for energy conservation, we have
and so we can find the value of K, the kinetic energy of the rock just before hitting the ground:
has converted into kinetic energy of motion
where h is the initial height of the rock, m its mass, and v its velocity just before hitting the water. So, for energy conservation, we have
and so we can find the value of K, the kinetic energy of the rock just before hitting the ground: