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3 years ago

Please i beg you. please

Chemistry

2 answers:

Reil [10]3 years ago

7 0

Answer:

A short-term environmental change is drought, smog, flooding, volcanic eruption, blizzards, and pollution this could happen in anyone of the food webs. That may effect how they will end up having to have to adapt to their environment so that they can continue to live there and not die off.

Explanation:

I don't know the second one

Elden [556K]3 years ago

6 0

Second one would be development of homes for humans. Causes a disturbance in everything for the animals. Lost of homes, food sources, mates. Bc if you start building in an area that was all forest it confuses the animals

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A space shuttle is used for space------

Gre4nikov [31]

Answer: YES THATS TRUE

Explanation:

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3 years ago

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Explain why two thin sweaters feel warmer then one thick sweater

jeyben [28]

Answer:

Two slender woolen sweaters are hotter than a thick woolen sweater in light of the fact that there is a layer of air between them that doesn't permit our body warmth to get away yet it likewise it doesn't retains heat from the climate and fleece is additionally a protector that itself doesn't permit our body warmth to get away

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3 years ago

The equilibrium constant for the reaction AgBr(s) Picture Ag+(aq) + Br− (aq) is the solubility product constant, Ksp = 7.7 × 10−

barxatty [35]

Answer:

The reaction will be non spontaneous at these concentrations.

Explanation:

$AgBr(s)\rightarrow Ag^+(aq) + Br^- (aq)$

Expression for an equilibrium constant $K_c$ :

$K_c=\frac{[Ag^+][Br^-]}{[AgCl]}=\frac{[Ag^+][Br^-]}{1}=[Ag^+][Br^-]$

Solubility product of the reaction:

$K_{sp}=[Ag^+][Br^-]=K_c=7.7\times 10^{-13}$

Reaction between Gibb's free energy and equilibrium constant if given as:

$\Delta G^o=-2.303\times R\times T\times \log K_c$

$\Delta G^o=-2.303\times R\times T\times \log K_{sp}$

$\Delta G^o=-2.303\times 8.314 J/K mol\times 298 K\times \log[7.7\times 10^{-13}]$

$\Delta G^o=69,117.84 J/mol=69.117 kJ/mol$

Gibb's free energy when concentration $[Ag^+] = 1.0\times 10^{-2} M$ and $[Br^-] = 1.0\times 10^{-3} M$

Reaction quotient of an equilibrium = Q

$Q=[Ag^+][Br^-]=1.0\times 10^{-2} M\times 1.0\times 10^{-3} M=1.0\times 10^{-5}$

$\Delta G=\Delta G^o+(2.303\times R\times T\times \log Q)$

$\Delta G=69.117 kJ/mol+(2.303\times 8.314 Joule/mol K\times 298 K\times \log[1.0\times 10^{-5}])$

$\Delta G=40.588 kJ/mol$

For reaction to spontaneous reaction: $\Delta G$ .
For reaction to non spontaneous reaction: $\Delta G>0$ .

Since ,the value of Gibbs free energy is greater than zero which means reaction will be non spontaneous at these concentrations

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3 years ago

What differs from between a radioactive isotope and a stable isotope

Digiron [165]

A stable isotope has just the right number of neutrons for the number of protons (the n:p ratio) to hold the nucleus together against the repulsions of the protons.

A radioactive isotope has either too few or too many neutrons for the nucleus to be stable,

The nucleus will then emit alpha, beta, or gamma radiation in an attempt to become more stable.

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4 years ago

Covalent bonds usually occur between atoms that have

marta [7]

Answer: A: high ionization energies; high electron affinitlies.

Explanation: Covalent bonds are basically about sharing of electrons between two atoms to achieve that stable structure. They are formed between two atoms when both have similar tendencies to attract electrons to themselves (i.e., when both atoms have identical or fairly similar ionization energies and electron affinities). Covalent bonding usually occurs between two non-metals.

For effective and proper bonding, the two atoms involved in the covalent bonding exercise should be small and hungry for electrons. This is to enable the nuclei of both atoms to effectively attract and hold the shared electron(s) in place; hence, the need for high ionization energies & high electron affinities for a more effective covalent bonding.

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3 years ago