Answer:
The correct answer is - C. Increasing the concentration increases the reaction rate.
Explanation:
In the given question the data with change in different factors affect the rate of reaction differently as it alters the time it takes to complete reaction:
Conditions Reaction Time
Original 10 seconds
Higher concentration 5 seconds
Higher temperature 5 seconds
Metal added 5 seconds
As it is given above, time is decreased in each condition including in the case of increasing the concentration of the reactants which means the rate of reaction increases as well.
Let's start to understand this question by a simple combustion reaction involving oxidation of Ethane in the presence of Oxygen. When Ethane is burned in the presence of Oxygen it produces Carbon Dioxide and Water respectively. Therefore, the equation is as,
C₂H₆ + O₂ → CO₂ + H₂O
Above reaction shows the reaction and the equation is unbalanced. Balancing chemical equation is important because according to law of conservation of mass, mass can neither be created nor destroyed. Hence, we should balance the number of elements on both side.
LHS RHS
Carbon Atoms 2 1
Hydrogen Atoms 6 2
Oxygen Atoms 2 3
It means this equation is not obeying the law. Now, how to balance? One way is as follow,
C₂H₆ + O₃ → C₂O₂ + H₆O
LHS RHS
Carbon Atoms 2 2
Hydrogen Atoms 6 6
Oxygen Atoms 3 3
We have balanced the equation by changing the subscripts. But, we have messed up the chemical composition of compounds and molecules like Oxygen is converted into Ozone.
Therefore, we will change the coefficients (moles) to balance the equation as,
C₂H₆ + 7/2 O₂ → 2 CO₂ + 3 H₂O
LHS RHS
Carbon Atoms 2 2
Hydrogen Atoms 6 6
Oxygen Atoms 7 7
Now, by changing the coefficients we have balanced the equation without disturbing the chemical composition of compounds and molecules.
Answer:
around 300
Explanation:
i did a science experiment on it :)
Answer:
It is true. a) 0.25 mol
Explanation:
<em>Hello </em><em>there?</em>
To begin solving this problem, you have to write down the chemical equation and make sure it is well balanced.
The chemical equation is;
3Mg(s) + N2(g) => Mg3N2(s)
1 mole of Mg = 24g
We have 18g of Magnesium (Mg) reacting with Nitrogen gas (N2)
From our equation,
Mole ratio = 3 : 1, (Mg : N2)
1 mol Mg = 24g
x mol Mg = 18g
x mol Mg = (18/24) = 0.75 mol Mg
But mole ratio = 3 : 1 (Mg : N2)
This means that 3 => 0.75 mol Mg
What about ratio 1 of N2?
N2 = (0.75 mol ÷ 3)/1
= 0.25 mol N2
<em>I </em><em>hope</em><em> </em><em>this </em><em>helps</em><em> </em><em>you </em><em>to </em><em>understand</em><em> </em><em>better</em><em>.</em><em> </em><em>Ha</em><em>v</em><em>e </em><em>a </em><em>nice </em><em>studies.</em><em> </em><em />
