1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Gala2k [10]
3 years ago
12

BRAINLIESTT ASAP! PLEASE HELP ME :)

Chemistry
1 answer:
ruslelena [56]3 years ago
7 0

Answer:

See below  

Step-by-step explanation:

Matter is either a <em>pure substance</em> or a <em>mixture. </em>

Pure substances

  • Are composed of one type of atom or molecule.
  • Have a constant chemical composition
  • Have fixed chemical properties
  • Have fixed physical properties

              • For example, melting point, boiling point, density, solubility

Mixtures:

  • Consist of two or more substances not chemically combined
  • Have a variable composition
  • Can be separated into two or more components by physical means

             • For example, filtration, distillation, centrifugation

  • Each component retains its own properties
You might be interested in
How old is a piece of wood that has 0.7813% of the carbon-14 of a living organism
MArishka [77]

Answer:

About 21*.3 years old

Explanation:

4 0
3 years ago
A gas has a volume of 1.8Lat−26◦Cand 147 kPa. At what temperature would the gas occupy 1.33 L at 217 kPa?
miss Akunina [59]

Answer: At temperature of 269 K the gas would occupy 1.33 L at 217 kPa

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 147 kPa

P_2 = final pressure of gas = 217 kPa

V_1 = initial volume of gas = 1.8 L

V_2 = final volume of gas = 1.33 L

T_1 = initial temperature of gas = -26^oC=273-26=247K

T_2 = final temperature of gas = ?

Now put all the given values in the above equation, we get:

\frac{147kPa\times 1.8L}{247K}=\frac{217kPa\times 1.33L}{T_1}

T_2=269K

Thus at 269 K temperature the gas would occupy 1.33 L at 217 kPa

3 0
4 years ago
What was Hubble's Discovery in the 1920s​
slavikrds [6]

Answer:

In the 1920s, Hubble was among the first to recognize that there is a universe of galaxies located beyond the boundaries of our Milky Way. During the 1920s, Edwin Hubble observed stars that vary in brightness in a patch of light known at the time as the Andromeda nebula.

8 0
2 years ago
Arrange follwoing substances from lowest to highest lattice energy" MgS, KI, GAN, LiBr
sleet_krkn [62]

Answer: KI, LiBr, MgS,GaN

Explanation:

Ionic sizes are the deciding factor in lattice energy. The smaller the ion, the higher the lattice energy. Since K+> Li+ and I- is larger than Br-, LiBr will have a higher lattice energy. The size of the sulphide ion is much smaller than the nitride ion but the Gallium is much smaller due to lanthanide contraction hence the answer.

7 0
3 years ago
Save the ________ used to extract metals.
MrRa [10]

Answer:

Save the *minerals* used to extract metals.

6 0
3 years ago
Other questions:
  • A simple machine produces 25 joules of output work for every 50 joules of input work . What is the efficiency of this machine ?
    13·1 answer
  • Distance from shore (in cm) Depth
    12·1 answer
  • How does thermal energy flow?
    9·1 answer
  • Which of The following correctly describes the graph (1 point)
    6·1 answer
  • Which vitamin is more soluble in water ? explain
    12·1 answer
  • Many monatomic ions are found in seawater, including the ions formed from the following list of elements. Write the Lewis symbol
    12·1 answer
  • Which of the following choices tells a computer how to preform a certain task?
    10·1 answer
  • Changes that occur during a chemical reaction are represented by a(n) _?_.
    9·1 answer
  • What is the formula for the compound iodine trichoride?
    15·1 answer
  • HELLO, DONT ANSWER THIS ITS FOR MY FRIEND
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!