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Zina [86]
3 years ago
14

The value of a car decreases by 20 percent per year. Mr. Sing purchases a $22,000 automobile. What is the value of the car at th

e end of the second year?
$14,080

$17,600

$19,800

$26,400
Mathematics
2 answers:
DiKsa [7]3 years ago
6 0

Answer:

The answer is 14,080

Step-by-step explanation:

got it right

aniked [119]3 years ago
3 0

Answer:

$14,080


Step-by-step explanation:


<u>At end of first year:</u>

$22,000 will decrease by 20%.<em> </em><em>It means to subtract 20% of 22,000 from 22,000. </em>

20% of 22,000 is  (0.2)(22,000)=4,400

Now, 22,000-4,400=17,600


<u>At end of second year:</u>

$17,600 will decrease by 20%. It means to subtract 20% of 17,600 from 17,600.

20% of 17,600 is  (0.2)(17,600)=3520

Now,  17,600-3,520=14,080


Hence, $14,080 is the value of the car at the end of 2 years. First answer choice is right.

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Answer:

A 24

Step-by-step explanation:

Assuming this is a right triangle, we can use the Pythagorean theorem

a^2+ b^2 = c^2

a^2 + 7^2 = 25^2

a^2 +49= 625

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a^2 +49-49 = 625-29

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sqrt(a^2) = sqrt(576)

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olganol [36]
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4 years ago
a total eclipse in 2003 lasted 2 17/24,minutes in 2005 it lasted 3/8 of a minute how much longer did it last in 2003
Doss [256]

Answer:

Total eclipse was 2\frac{1}{3} minutes longer than in 2005.

Step-by-step explanation:

It is given in the question that total eclipse in 2003 lasted 2\frac{17}{24} minutes and in 2005 it lasted 3/8 of a minute.

We have to calculate how much longer did it last in 2003.

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\frac{48+17}{24}-\frac{3}{8}

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