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2 years ago

What is the mass of Al₂O3 that will contain 10 kg of aluminium?

Chemistry

2 answers:

Oksanka [162]2 years ago

5 0

Answer:

1 mole of Al2O3 = 102 grams

1 mole of Al2 = 54 grams

102 grams of Al2O3 contains = 54 gram of Al2

10kg of Al2O3 contains = (54/102)*10000g Al2

= 5294.11 g Al2 or 5.29411 kg

fredd [130]2 years ago

4 0

Answer:

108

Explanation:

Molar mass of Al2O3 = (27 × 2) + (16 × 3)

= 54 + 48 = 102 g/mol

Moles in 204 g of Al2O3 = 204 g/(102 g/mol)

2 mol

Mass of aluminum in 1 mol of Al2O3 = 27 g × 2

= 54 g

Mass of aluminum in 2 mol of Al2O3 = 54 g × 2

= 108 g

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We get 1700 Tonnes of Ammonia every day. How many tonnes of 63% Nitric acid we can get?

jeyben [28]

There are 3 equations involved in manufacturing Nitric Acid from Ammonia.

First the ammonia is oxidized:
4NH3 + 5O2 = 4NO + 6H2O

Then for the absorption of the nitrogen oxides.
2NO + O2 = N2O4

Lastly, the N2O4 is further oxidized into Nitric acid.
3N2O4 + 2H2O = 4HNO3 + 2NO

Then run stoichiometry through these equations.
The first equation produces roughly 271,722,938 grams of NO
The second equation produces roughly 416,606,944 grams of N2O4
The last equation produces roughly 380,412,294 grams of HNO3 (nitric acid)

Convert the exact number back into tons, and your answer is: 419.332775 tons.

Rounded, I'm going to say that's 419.33 tons.
Hope this helps! :)

Also, it seems that commercially, Nitric Acid is commonly made by bubbling NO2 into water, rather than using ammonia.

8 0

3 years ago

If I had 3.50 x 10 24molecules of Cl2 gas, how many grams is this?

Zinaida [17]

Answer:

412 g Cl₂

General Formulas and Concepts:

Atomic Structure

Reading a Periodic Table
Moles
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

Using Dimensional Analysis

Explanation:

Step 1: Define

[Given] 3.50 × 10²⁴ molecules Cl₂

[Solve] grams Cl₂

Step 2: Identify Conversions

Avogadro's Number

[PT] Molar Mass of Cl - 35.45 g/mol

Molar Mass of Cl₂ - 2(35.45) = 70.9 g/mol

Step 3: Convert

[DA] Set up: $\displaystyle 3.50 \cdot 10^{24} \ molecules \ Cl_2(\frac{1 \ mol \ Cl_2}{6.022 \cdot 10^{23} \ molecules \ Cl_2})(\frac{70.9 \ g \ Cl_2}{1 \ mol \ Cl_2})$
[DA] Divide/Multiply [Cancel out units]: $\displaystyle 412.072 \ g \ Cl_2$

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

412.072 g Cl₂ ≈ 412 g Cl₂

5 0

2 years ago

Which material is the lest likely to be recognized as a mixture by looking at it under a microscope ?

Lisa [10]

Hello,

The answer is option C homogeneous mixture.

Reason:

The answer is option C because you can find homogeneous mixtures anywhere for example: Vinegar. Its not option A because suspension is usually in elements but as not a mixture. Its not option B because a colloid is a measurement tool that allows to make compounds (mixtures).Its also not option D because those type o mixtures are hard to find in extreme weather conditions.

If you need anymore help feel free to ask me!

Hope this helps!

~Nonportrit

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3 years ago

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shusha [124]

Only one atom because atom with 17 electrons need that one electron to become stable

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3 years ago

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Which two equations represent double-replacement reactions?

enyata [817]

Answer: A and D, I believe