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lina2011 [118]
3 years ago
10

. A rectangular fish pond is 21 ft2 in area. If the owner can surround the pond with a 20-foot fence, what are the dimensions of

the pond?
Mathematics
1 answer:
prisoha [69]3 years ago
7 0

Answer:

It's 3 x 7 pond or a 7 x 3 pond

Step-by-step explanation:

Let the rectangular pond have dimensions l x b.

ATQ, l*b=21 and 2(l+b)=20. Solving it, we get l=3 or 7 and b=7 or 3.

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Of the following points, name all that lie on the same vertical line?
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Answer:

(-2,-6) (6,2)

Step-by-step explanation:

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3 years ago
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How to find the total surface area of a rectangular prism?
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If the length is taken as l , height is taken as h and breadth is taken as b . then

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hope that helps
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3 years ago
At Burnt Mesa Pueblo, archaeological studies have used the method of tree-ring dating in an effort to determine when prehistoric
Zanzabum

Answer:

a) (1215, 1297)

b) (1174,  1338)

c) (1133, 1379)      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 1256

Standard Deviation, σ = 41

Empirical Rule:

  • Also known as 68-95-99.7 rule.
  • It states that almost all the data lies within three standard deviation for a normal data.
  • About 68% of data lies within 1 standard deviation of mean.
  • About 95% of data lies within two standard deviation of mean.
  • About 99.7% of data lies within 3 standard deviation of mean.

a) range of years centered about the mean in which about 68% of the data lies

\mu \pm 1(\sigma)\\=1256 \pm 41\\=(1215, 1297)

68% of data will be found between 1215 years and 1297 years.

b) range of years centered about the mean in which about 95% of the data lies

\mu \pm 2(\sigma)\\=1256 \pm 2(41)\\=1256 \pm 82\\=(1174, 1338)

95% of data will be found between 1174 years and 1338 years.

c) range of years centered about the mean in which about all of the data lies

\mu \pm 3(\sigma)\\=1256 \pm 3(41)\\=1256 \pm 123\\=(1133, 1379)

All of data will be found between 1133 years and 1379 years.

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4 years ago
Multiply 0.07 and 11.2 by
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0.07 x 11.2 = 0.784 -< Answer

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3 years ago
Find the measure of each interior angle
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\bf \textit{sum of all interior angles of a polygon}\\\\&#10;180(n-2)\quad &#10;\begin{cases}&#10;n=\textit{number of sides}\\&#10;---------\\&#10;n=10&#10;\end{cases}\implies 180(10-2)\implies 1440\\\\&#10;-------------------------------\\\\&#10;\begin{array}{lclll}&#10;&x + 5\\&x + 10\\&x + 20\\&x + 30\\&x + 35\\&x + 40\\&x + 60\\&x + 70\\&x + 80\\+&x + 90\\&#10;&----\\&#10;&10x+440&#10;\end{array}\implies &#10;\begin{array}{llll}&#10;10x+440=1440&#10;\\\\\\&#10;10x=1000&#10;\\\\\\&#10;x=\cfrac{1000}{10}\implies x=100&#10;\end{array}

so.. to get every angle, simply plug in 10 for "x" for each.
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3 years ago
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