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rjkz [21]
3 years ago
15

This is easy can u help plss??

Mathematics
1 answer:
Maksim231197 [3]3 years ago
7 0

Answer:

28

Step-by-step explanation:

cause

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R=x(A+B)
divide both sides by x
R/x=A+B
minus B both sides
(R/x)-B=A
A=(R/x)-B
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How many triangles can you draw with side lengths 2cm, 3cm, and 8cm?
serg [7]

Answer: 1   /How: 2x3x8=_ when u get tha answer u do 2+3+8=180 which would come to one.

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Write three expressions that are equivalent to 2^6
aleksandr82 [10.1K]

Answer:

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4 0
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If the graph of f(x)= 3^x is reflected over the x-axis, what is the equation of the new graph?
Lerok [7]

Answer:

  • g(x) = - 3^x

Step-by-step explanation:

<u>Reflection over x-axis results in:</u>

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8 0
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Read 2 more answers
What is the value of "c" in the following quadratic? (Make sure the equation is in
garri49 [273]

               \rule{50}{1}\large\blue\textsf{\textbf{\underline{Given question:-}}}\rule{50}{1}

           <em>What is the value of c in the quadratic </em>\large\text{$x^2+28=-11x$}?

          \rule{50}{1}\large\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}

           Before starting to solve, you should notice something - the

quadratic is not in its standard form!

We can easily fix it by adding \large\textit{11x} on both sides:-

\large\text{$x^2+28-11x=0$}

We can switch the order of 28 and -11x:-

\large\text{$x^2-11x+28=0$}

  Now, the quadratic is in its standard form, so we can get down to

finding the value of "c".

Remember, the standard form of a quadratic looks like so:-

  •  \large\text{$ax^2+bx+c=0$}

Now we can just write our <u>quadratic</u> here:-

  • \large\text{$x^2-11x+28=0$}

Now, can you see what the value of "c" is?

An easy way to <u>remember</u> "c" in quadratics is:-

The "c" in quadratics is the constant.

   

Henceforth, we conclude that the value of "c" in the given quadratic is:-

 \Large\textbf{28}\Large\checkmark

<h3>         Good luck with your studies.</h3>

        \rule{50}{1}\smile\smile\smile\smile\smile\smile\rule{50}{1}    

5 0
2 years ago
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